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Answer:
- sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
- cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
- tan(Ф) = 4/5; cot(Ф) = 5/4
Step-by-step explanation:
The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.
   Tan = Opposite/Adjacent
   tan(Ф) = 4/5
This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:
   AC² = AB² +BC² = 5² +4² = 41
   AC = √41 . . . . . hypotenuse
Then the other trig functions are ...
   Sin = Opposite/Hypotenuse
   sin(Ф) = 4/√41 = (4/41)√41
   Cos = Adjacent/Hypotenuse
   cos(Ф) = 5/√41 = (5/41)√41
And the reciprocal functions are ...
   csc(Ф) = 1/sin(Ф) = (√41)/4
   sec(Ф) = 1/cos(Ф) = (√41)/5
   cot(Ф) = 1/tan(Ф) = 5/4
 
        
             
        
        
        
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The picture can be divided into 2 same triangles and one rectangular. 
The triangle areas is {1/2 *base * height}*2 (because 2 same triangles) 
and you need to sum rectangular area (width * base).
The result will be area of 2 triangle +area of rectangular.
=2(1/2*base of triangle* height)+ (base of rectangular * height)
= (base of triangle* height)+(base of rectangular * height)
=(base of triangle +base of rectangular)*height
b1 is top length
b2 is bottom length, and so
Base of triangle =(b1-b2/2)
Base of rectangular =b2
Height =h
Thus A ={(b1-b2/2)+b2 }*h
A= [(b1+b2)/2]*h
        
             
        
        
        
Answer:
hope this an helps
Step-by-step explanation: