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Afina-wow [57]
3 years ago
13

How can you tell if 2 figures are similar

Mathematics
1 answer:
S_A_V [24]3 years ago
8 0
When two figures are similar the ratios of the lenghts of their corresponding sides are equal
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Anyone know how to do trig? Given tan Ф = 4/5, find all other trig functions.
mars1129 [50]

9514 1404 393

Answer:

  • sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
  • cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
  • tan(Ф) = 4/5; cot(Ф) = 5/4

Step-by-step explanation:

The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.

  Tan = Opposite/Adjacent

  tan(Ф) = 4/5

This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:

  AC² = AB² +BC² = 5² +4² = 41

  AC = √41 . . . . . hypotenuse

Then the other trig functions are ...

  Sin = Opposite/Hypotenuse

  sin(Ф) = 4/√41 = (4/41)√41

  Cos = Adjacent/Hypotenuse

  cos(Ф) = 5/√41 = (5/41)√41

And the reciprocal functions are ...

  csc(Ф) = 1/sin(Ф) = (√41)/4

  sec(Ф) = 1/cos(Ф) = (√41)/5

  cot(Ф) = 1/tan(Ф) = 5/4

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Haley placed 5 of the bookmarks end to end Draw a point on the number line below to represent the total length of the 5 bookmark
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Help and show explanation please
Dennis_Churaev [7]
The picture can be divided into 2 same triangles and one rectangular.

The triangle areas is {1/2 *base * height}*2 (because 2 same triangles)

and you need to sum rectangular area (width * base).
The result will be area of 2 triangle +area of rectangular.
=2(1/2*base of triangle* height)+ (base of rectangular * height)
= (base of triangle* height)+(base of rectangular * height)
=(base of triangle +base of rectangular)*height

b1 is top length
b2 is bottom length, and so

Base of triangle =(b1-b2/2)
Base of rectangular =b2
Height =h
Thus A ={(b1-b2/2)+b2 }*h
A= [(b1+b2)/2]*h
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Step-by-step explanation:

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