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Afina-wow [57]
3 years ago
13

How can you tell if 2 figures are similar

Mathematics
1 answer:
S_A_V [24]3 years ago
8 0
When two figures are similar the ratios of the lenghts of their corresponding sides are equal
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Answer this question please and thank you
Georgia [21]

0.377 + 5.51 = 5.887

Sorry I can only solve the first one. Could you give me a hint on how to do the second one ?

5 0
2 years ago
Read 2 more answers
HELP THIS IS DUE SOON PLEASEEEEEEEEEEEE HELPPPPPPPPPP
muminat

Answer:

6x^2 + 4x

Step-by-step explanation:

g(x) + f(x)

= -8x^2 - 3x + 5 + 2x^2 + 7x - 5

= -8x^2 + 2x^2 - 3x + 7x + 5 - 5

= - 6x^2 + 4x

4 0
3 years ago
Solve 7x- c= k for x. <br>A. X = 7(k+C) <br>B. x = 7(K-C) <br>C. X = k+c/7 <br>D. X= k-c/7​
antoniya [11.8K]

Answer:

C

Step-by-step explanation:

you add c to both side which will then make it 7x=k+c then you would divide 7 from both sides leaving you with x=k+c/7. Except 7 will be under the k and c.

7 0
3 years ago
Find the x-intercept of the line whose equation is 8x + 2y = 4.<br> 04<br> 02<br> 1/2
bezimeni [28]

Answer:

1/2

Step-by-step explanation:

The x-intercept is a point on the graph that is located on any point of x but must have a y-value of 0. To find the x-intercept, we must set y in the given equation equal to 0.

8x + 2y = 4

8x + 2(0) = 4

8x = 4

x = 4/8

x = 1/2

4 0
2 years ago
Find the rectangular coordinates of the point (squareroot3, pi/6)
svet-max [94.6K]

Answer:

The rectangular coordinates of the point are (3/2 , √3/2)

Step-by-step explanation:

* Lets study how to change from polar form to rectangular coordinates

- To convert from polar form (r , Ф) to rectangular coordinates (x , y)

 use these rules

# x = r cos Ф

# y = r sin Ф

* Now lets solve the problem

∵ The point in the rectangular coordinates is (√3 , π/6)

∴ r = √3 and Ф = π/6

- Lets find the x-coordinates

∵ x = r cos Ф

∵ r = √3

∵ Ф = π/6

∴ x = √3 cos π/6

∵ cos π/6 = √3/2

∴ x = √3 (√3/2) = 3/2

* The x-coordinate of the point is 3/2

- Lets find the y-coordinates

∵ y = r sin Ф

∵ r = √3

∵ Ф = π/6

∴ y = √3 sin π/6

∵ sin π/6 = 1/2

∴ y = √3 (1/2) = √3/2

* The y-coordinate of the point is √3/2

∴ The rectangular coordinates of the point are (3/2 , √3/2)

6 0
3 years ago
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