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Ray Of Light [21]
3 years ago
6

Find the rectangular coordinates of the point (squareroot3, pi/6)

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

The rectangular coordinates of the point are (3/2 , √3/2)

Step-by-step explanation:

* Lets study how to change from polar form to rectangular coordinates

- To convert from polar form (r , Ф) to rectangular coordinates (x , y)

 use these rules

# x = r cos Ф

# y = r sin Ф

* Now lets solve the problem

∵ The point in the rectangular coordinates is (√3 , π/6)

∴ r = √3 and Ф = π/6

- Lets find the x-coordinates

∵ x = r cos Ф

∵ r = √3

∵ Ф = π/6

∴ x = √3 cos π/6

∵ cos π/6 = √3/2

∴ x = √3 (√3/2) = 3/2

* The x-coordinate of the point is 3/2

- Lets find the y-coordinates

∵ y = r sin Ф

∵ r = √3

∵ Ф = π/6

∴ y = √3 sin π/6

∵ sin π/6 = 1/2

∴ y = √3 (1/2) = √3/2

* The y-coordinate of the point is √3/2

∴ The rectangular coordinates of the point are (3/2 , √3/2)

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Step-by-step explanation:

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Answer:

hello

Step-by-step explanation:

adjacent angles are equal to 180 degrees,

(2x + 9) + (5x + 3) = 180 \\   8x + 12 = 180 \\ 8x = 180 - 12 \\ 8x = 168 \\ x  =  \frac{168}{8}  \\ x = 21  \\  \\

but, for some reason, does not match the answers…

Can the answers be wrong?

or I miscalculated…

i hope it helps have a nice day

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Read 2 more answers
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