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Alecsey [184]
3 years ago
7

Solve by substitution. 3x-y=5 -2x+y=0

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
First, rewrite the equation -2x+y=0 into y-mx+b format. This is y=2x+0. We can then substitute this into our first equation.
3x-y=5
turns into
3x-2x=5
x=5
We can then plug in our value for x to find y.
3(5)-y=0
simplifies into
15-y=0
Simplify this to get that y=15
You can then plug these into the other equation ot make sure it's right.
-2(5)+15=5
-10+15=5
which is 5=5 (true)

So your answers are x=5 and y=15.

:)
Citrus2011 [14]3 years ago
3 0
In order to use substitution, you need to isolate a variable on one of the equations:

-2x+y=0
y=2x

Then you plug that equation into the other equation. Since we isolated y, we plug in 2x for y in the other equation:

3x-(2x)=5
x=5

Then plug the value you found into any equation to solve for the other variable:

3(5)-y=5
15-y=5
-y=-10
y=10

So your answers are x=5, y=10
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Given that f(x) = 5x^2-3x+7 and f(g(x))=(5x^4)/9 + (17x^2)/3 + 21. Find all possible values for the sum of the coefficients in t
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steps

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refine

x=5x^2-3x+7

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Jared creates a number sequence that has a first term of 2 and a second of term of 5. Each term after the second is created by s
dexar [7]

The rule for the sequence is S(n) = 2S(n-1) - S(n-2)

Alternative form: S(n) = S(n-1) + 3

Step-by-step explanation:

In this problem, we know the first two terms of the sequence:

S(1) = 2

S(2) = 5

We are told that each term after the second is created by subtracting the term before the previous term from twice the previous term. In other words, if we call:

S(n) the current term

S(n-1) the previous term

S(n-2) the term before the previous term

This statement translates into the following sequence:

S(n) = 2S(n-1) - S(n-2)

Because we are subtracting the term before the previous term, S(n-2), from twice the previous term, 2S(n-1).

We can apply now the rule to find the first few terms of the sequence after S(1) and S(2):

S(3) = 2S(2) - S(1) = 2(5)-2=10-2 = 8

S(4) = 2S(3) - S(2) = 2(8)-5=16-5 = 11

S(5) = 2S(4) - S(3) = 2(11)-8=22-8 = 14

We notice also that each term of the sequence is just equal to the previous term plus 3, so the sequence can also be written as

S(n) = S(n-1) + 3

Learn more about sequences:

brainly.com/question/1522572

brainly.com/question/3280369

#LearnwithBrainly

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