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3 years ago

Solve by substitution. 3x-y=5 -2x+y=0

2 answers:

7 0

First, rewrite the equation -2x+y=0 into y-mx+b format. This is y=2x+0. We can then substitute this into our first equation.
3x-y=5
turns into
3x-2x=5
x=5
We can then plug in our value for x to find y.
3(5)-y=0
simplifies into
15-y=0
Simplify this to get that y=15
You can then plug these into the other equation ot make sure it's right.
-2(5)+15=5
-10+15=5
which is 5=5 (true)

So your answers are x=5 and y=15.

:)

Citrus2011 [14]3 years ago

3 0

In order to use substitution, you need to isolate a variable on one of the equations:

-2x+y=0
y=2x

Then you plug that equation into the other equation. Since we isolated y, we plug in 2x for y in the other equation:

3x-(2x)=5
x=5

Then plug the value you found into any equation to solve for the other variable:

3(5)-y=5
15-y=5
-y=-10
y=10

So your answers are x=5, y=10

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A(t) = (t – k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.

mr Goodwill [35]

the absolute value of the product of the zeros of a is $-108$ .

<u>Step-by-step explanation:</u>

Here we have , $a(t) = (t - k)(t - 3)(t - 6)(t + 3)$ is a polynomial function of t, where k is a constant. Given that a(2) = 0 . We need to find the absolute value of the product of the zeros of a . Let's find out:

Equation every factor of a(t) to zero we get:

⇒ $a(t) = (t - k)(t - 3)(t - 6)(t + 3) = 0$

⇒ $(t - k) =0\\(t - 3)=0\\(t - 6)=0\\(t + 3) = 0$

⇒ $t =k\\t =3\\t = 6\\t =- 3$

But , t=2 So , $k=2$ . Now , the absolute value of the product of the zeros of a is :

⇒ $k(3)(6)(-3)$

⇒ $2(3)(6)(-3)$

⇒ $-108$

Therefore, the absolute value of the product of the zeros of a is $-108$ .

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3 years ago

Why do ⅚, 15,18, and 10/12 equal each other?

Burka [1]

10/12 is an un simplified form of 5/6.

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3 years ago

Choose the best description for the real number 34/3

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4 years ago

For circle H, JN = x, NK = 2, LN = 3, and NM = 6. Solve for x.

Advocard [28]

Answer:

The value of x is 9 ⇒ C

Step-by-step explanation:

In a circle, if two chords intersected at a point inside it there are four segments created, two in each cord, the products of the lengths of the line segments on each chord are equal.

<em>Let us use this rule to solve the question</em>

In circle H

∵ Jk and LM are chords intersected at point N inside the circle

∴ The created segments are JN, Nk, and LN, NM

→ By using the rule above

∴ JN × NK = LN × NM

∵ JN = x and NK = 2

∵ LN = 3 and NM = 6

→ Substitute these values in the equation above

∴ x × 2 = 3 × 6

∴ 2x = 18

→ Divide both sides by 2 to find x

∴ $\frac{2x}{2}=\frac{18}{2}$

∴ x = 9

∴ The value of x is 9

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3 years ago

Ashley deposits $1000 into an account that earns 4% interest compounded 2 times per year. how much money will Ashley have in her

loris [4]

The equation for compound interest is $A=P(1+\frac{r}{n})^{nt}$ , where:
P is the original deposit (or "principal")
r is the rate of the interest (in decimal form)
n is the number of times per year that the interest is compounded
t is the time passed in years

Plugging in your values, we see that the equation becomes $A=1000(1+\frac{.04}{2})^{(2)(5)}=1000(1.02)^{10}$

which equals, to the nearest cent, $1218.99, which is answer C.

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