Positive fractions less than 1,with interval of 1/8 between each pair of fractions

Multiply or divide, write your answer in scientific notation.

Sidana [21]

1.44/2.4 • 10^10/10^2
= 6 • 10^7 in scientific notation

7 0

3 years ago

Factorize 3x(a-2)-6(a-2)

creativ13 [48]

(3x(a)-6x)- (6a-12) Multiply the outside with the inside

3 0

4 years ago

X-1/2=15 1/4 whats x and show work

ikadub [295]

X-1/2=15 1/4

15 1/4 = 15*4 + 1 = 61/4

61/4

x - 1/2 = 61/4
+1/2 +1/2

61/4 + 2/4 = 63/4

x = 63/4

7 0

3 years ago

Which statements about the factors of the terms in the expression 20 a + 15 a b + 24 b are true? Select three options.

ExtremeBDS [4]

Answer:

Following are the true statements

2. The factors common to 20a and 15ab are 1, 5, and a.

3. The factors common to 20a and 24b are 1, 2, and 4.

5. The GCF of the expression is 1

Step-by-step explanation:

Expression is 20a + 15ab + 24b

Now lets have a look at each of the options provided!

1. The factors common to 20a and 15ab are 1, 5, a, and b.

False

As you can see there is no b in 20a term only 1,5,a are common hence it is false.

2. The factors common to 20a and 15ab are 1, 5, and a.

True

The terms 20a and 15ab are divisible by 1,5,a hence it is true.

3. The factors common to 20a and 24b are 1, 2, and 4.

True

The terms 20a and 24b are divisible by 1,2,4 hence it is true

4. The GCF of the expression is ab.

False

20a + 15ab + 24b

As you can see ab is not common in all of the terms hence it cannot be greatest common factor

5. The GCF of the expression is 1

True

Factor of 20 are: 2,2,5,1

Factor of 15 are: 3,5,1

Factor of 24 are: 2,2,2,3,1

As you can see the only common factor among all the terms is 1 hence GCF is 1.

5 0

3 years ago

Question 6 (1.25 points)

Lisa [10]

Answer:

Test statistic Z= 1.713

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

Step-by-step explanation:

Step(i):-

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

H₀: x⁻ = μ

Alternative Hypothesis : x⁻ ≠ μ

Step(ii):-

Test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }$

Z = 1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value = 1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the mean annual salary of all lawyers in a city is different from $110,000

4 0

3 years ago