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lidiya [134]
3 years ago
10

answer fast I will reward 50 points [] are the exponents Use the given information to complete parts I and II. In your final ans

wer, include all calculations. Planet Earth has an approximate diameter of 1.2742 · 10 [10] millimeters. The sun has a diameter of 1.391 · 10 [6] kilometers. Part I: Given that for every one kilometer there are 1,000,000 millimeters, which unit of measurement should be used to best represent the lengths of the sun and Earth's diameters? Part II: Approximate how many times greater the sun's diameter is than planet Earth's.
Mathematics
2 answers:
EleoNora [17]3 years ago
8 0

Answer:

see below

Step-by-step explanation:

given;

Planet Earth has an approximate diameter of 1.2742 x 10¹⁰ millimeters.

The sun has a diameter of 1.391 x 10⁶ kilometers.

find:

Part I:

Given that for every one kilometer there are 1,000,000 millimeters, which unit of measurement should be used to best represent the lengths of the sun and Earth's diameters?

Part II:

Approximate how many times greater the sun's diameter is than planet Earth's.

-------------------------------------------------------------------------------------------------------

part I:

the best measurement to represent the lengths of the sun and Earth's diameters is kilometers.

= planet dia. = 1.2742 x 10¹⁰ mm x  <u>          1 km         </u>    =  12,742 km  

                                                          1,000,000 mm

= sun dia. = 1.391 x 10⁶ km = 1,391 x 10³ km = 1,391,000 km

part II:

the approximate scale dia ratio of earth to sun is = sun dia. over earth's dia.

=  <u>1,391,000 km</u>

    12,742 km

= 109.17 times

therefore,

109.17 times greater the sun's diameter is than planet Earth's.

Sloan [31]3 years ago
5 0

Answer:

Planet Earth has an approximate diameter of 1.2742 x 10¹⁰ millimeters.

The sun has a diameter of 1.391 x 10⁶ kilometers.

find:

Part I:

Given that for every one kilometer there are 1,000,000 millimeters, which unit of measurement should be used to best represent the lengths of the sun and Earth's diameters?

Part II:

Approximate how many times greater the sun's diameter is than planet Earth's.

-------------------------------------------------------------------------------------------------------

part I:

the best measurement to represent the lengths of the sun and Earth's diameters is kilometers.

= planet dia. = 1.2742 x 10¹⁰ mm x            1 km            =  12,742 km  

                                                         1,000,000 mm

= sun dia. = 1.391 x 10⁶ km = 1,391 x 10³ km = 1,391,000 km

part II:

the approximate scale dia ratio of earth to sun is = sun dia. over earth's dia.

=  1,391,000 km

   12,742 km

= 109.17 times

therefore,

109.17 times greater the sun's diameter is than planet Earth's.

Step-by-step explanation:

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7 0
3 years ago
Which methods correctly solve for the variable n in the equation 11−n=−20? Select all that apply. First, add n to both sides. Th
Zina [86]

Answer:

First, subtract 11 from both sides. Then, multiply both sides by −1.

First, add n to both sides. Then, add 20 to both sides.

Step-by-step explanation:

Given equation:

11 - n = -20

Solve for variable n

11 - n = -20

Subtract 11 from both sides

11 - n - 11 = -20 - 11

- n = - 31

Multiply both sides by -1

- n(-1) = - 31(-1)

n = 31

First, subtract 11 from both sides. Then, multiply both sides by −1.

11 - n = -20

11 -n +n = -20 + n

11 = -20 + n

11 + 20 = -20 + n +20

31 = n

First, add n to both sides. Then, add 20 to both sides.

First, subtract n from both sides. Then, multiply both sides by −20.

First, add n to both sides. Then, subtract 11 from both sides.

11 - n = -20

11 - n +n = -20 + n

11 = -20 + n

11 - 11 = -20 + n -11

Not possible

First, subtract 11 from both sides. Then, multiply both sides by −1.

First, add n to both sides. Then, subtract 20 from both sides.

11 - n = -20

11 - n + n = -20 + n

11 = -20 + n

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Not possible

5 0
3 years ago
_ 5x^20-7x^10+15 in quadratic form
Tpy6a [65]

Answer:

x = -(sqrt(349) - 7)^(1/10)/10^(1/10) or x = (sqrt(349) - 7)^(1/10)/10^(1/10) or x = -((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -(1/10 (-7 - sqrt(349)))^(1/10) or x = (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(1/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(1/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(2/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(2/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(3/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(3/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(4/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(4/5) (1/10 (-7 - sqrt(349)))^(1/10)

Step-by-step explanation:

Solve for x:

-5 x^20 - 7 x^10 + 15 = 0

Substitute y = x^10:

-5 y^2 - 7 y + 15 = 0

Divide both sides by -5:

y^2 + (7 y)/5 - 3 = 0

Add 3 to both sides:

y^2 + (7 y)/5 = 3

Add 49/100 to both sides:

y^2 + (7 y)/5 + 49/100 = 349/100

Write the left hand side as a square:

(y + 7/10)^2 = 349/100

Take the square root of both sides:

y + 7/10 = sqrt(349)/10 or y + 7/10 = -sqrt(349)/10

Subtract 7/10 from both sides:

y = sqrt(349)/10 - 7/10 or y + 7/10 = -sqrt(349)/10

Substitute back for y = x^10:

x^10 = sqrt(349)/10 - 7/10 or y + 7/10 = -sqrt(349)/10

Taking 10^th roots gives (sqrt(349)/10 - 7/10)^(1/10) times the 10^th roots of unity:

x = -(1/10 (sqrt(349) - 7))^(1/10) or x = (1/10 (sqrt(349) - 7))^(1/10) or x = -(-1)^(1/5) (1/10 (sqrt(349) - 7))^(1/10) or x = (-1)^(1/5) (1/10 (sqrt(349) - 7))^(1/10) or x = -(-1)^(2/5) (1/10 (sqrt(349) - 7))^(1/10) or x = (-1)^(2/5) (1/10 (sqrt(349) - 7))^(1/10) or x = -(-1)^(3/5) (1/10 (sqrt(349) - 7))^(1/10) or x = (-1)^(3/5) (1/10 (sqrt(349) - 7))^(1/10) or x = -(-1)^(4/5) (1/10 (sqrt(349) - 7))^(1/10) or x = (-1)^(4/5) (1/10 (sqrt(349) - 7))^(1/10) or y + 7/10 = -sqrt(349)/10

Subtract 7/10 from both sides:

x = -(sqrt(349) - 7)^(1/10)/10^(1/10) or x = (sqrt(349) - 7)^(1/10)/10^(1/10) or x = -((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or y = -7/10 - sqrt(349)/10

Substitute back for y = x^10:

x = -(sqrt(349) - 7)^(1/10)/10^(1/10) or x = (sqrt(349) - 7)^(1/10)/10^(1/10) or x = -((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x^10 = -7/10 - sqrt(349)/10

Taking 10^th roots gives (-7/10 - sqrt(349)/10)^(1/10) times the 10^th roots of unity:

Answer:  x = -(sqrt(349) - 7)^(1/10)/10^(1/10) or x = (sqrt(349) - 7)^(1/10)/10^(1/10) or x = -((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(1/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(2/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(3/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = ((-1)^(4/5) (sqrt(349) - 7)^(1/10))/10^(1/10) or x = -(1/10 (-7 - sqrt(349)))^(1/10) or x = (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(1/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(1/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(2/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(2/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(3/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(3/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = -(-1)^(4/5) (1/10 (-7 - sqrt(349)))^(1/10) or x = (-1)^(4/5) (1/10 (-7 - sqrt(349)))^(1/10)

8 0
3 years ago
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