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Shalnov [3]
3 years ago
12

Consider the following figure.

Mathematics
1 answer:
Karolina [17]3 years ago
4 0

Answer:

BD = 16

Step-by-step explanation:

By applying mean proportional theorem in the given right triangles,

\frac{AD}{BD}=\frac{BD}{CD}

AD × CD = BD²

8 × 32 = BD²

BD = √256

BD = 16

Therefore, measure of side BD = 16 units.

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cattie started with 12 ounces of water when she began her walk when she finished walking she had 2 1/4 ounces of water left how
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It is 9 3/4 because 12- 2 1/4 is 9 /14
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If we graph a circle whose center is at (1, -3), the center is located at the __________ quadrant
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Answer:

Quadrant IV

Step-by-step explanation:

If the circle's center is located at (1, -3), then its center is located in the 4th Quadrant.

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2 years ago
If angle∠ a and angle∠ b are supplementary angles and angle∠ a is nine nine times as large as angle∠ ​b, find the measures of an
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A+b=180
a=9b
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3 years ago
What number has exactly 5 factors between 1 and 20
mariarad [96]
<span>The factors of 16 are 1, 2, 4, 8, and 16.</span>
3 0
3 years ago
Read 2 more answers
Malik has a bag with 7 green marbles and 3 black marbles.
Fynjy0 [20]

1) Probability: 7/30 (or 23.3%)

2) Probability: 21/100 (or 21.0%)

Step-by-step explanation:

1)

At the beginning, there are 10 marbles in total in the bag, of which 7 are green and 3 are blacks.

So the probability of choosing a green marble as first is:

p(g)=\frac{7}{7+3}=\frac{7}{10}

Then, after he picked a green marble, there are only 9 marbles left in the bag, of which 6 are green and 3 are black. Therefore, at the second time, the probability of choosing a black marble will be

p(b)=\frac{3}{3+6}=\frac{3}{9}=\frac{1}{3}

Therefore, the probability that Malik will draw a green marble first and then a black marble is the product of the two probabilities:

p(gb)=p(g)p(b)=\frac{7}{10}\cdot \frac{1}{3}=\frac{7}{30}

In percentage, this is \frac{7}{30}\cdot 100 =23.3\%

2)

In this second case, the same experiment is repeated by this time the first ball is put back into the back after the  first draw.

The probability that Malik will draw a green marble at the first attempt is the same as before:

p(g)=\frac{7}{7+3}=\frac{7}{10}

Later, the green marble is put back in the bag, so we still have 7 green marbles and 3 black marbles. Therefore, the probability of choosing a black marble at the second draw is

p(b)=\frac{3}{3+7}=\frac{3}{10}

Therefore, the overall probability is

p(gb)=p(g)p(b)=\frac{7}{10}\cdot \frac{3}{10}=\frac{21}{100}

In percentage, \frac{21}{100}\cdot 100 = 21.0\%

3)

The probability in the second case is lower because in the second case, the green marble is put back into the bag after the first draw, therefore at the second draw the probability of choosing a black marble is less than the first case (because in the 2nd case, there are more marbles in total to choose from, so the probability of choosing a black marble will be less).

Learn more about probability:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

#LearnwithBrainly

3 0
4 years ago
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