9514 1404 393
Answer:
- area: 114 square units
- perimeter: 44 units
Step-by-step explanation:
The figure is a trapezoid with bases 12 and 7, and a height of 12. The area formula is ...
A = (1/2)(b1 +b2)h
A = (1/2)(12 +7)(12) = 114 . . . square units area
__
The length of side AB can be found using the distance formula:
d = √((x2 -x1)^2 +(y2 -y1)^2)
d = √((6 -(-6))^2 +(1 -6)^2) = √(144 +25) = 13
The sum of the side lengths is then ...
13 +7 +12 +12 = 44 . . . units perimeter
Answer:
the answer simplified is 24
Step-by-step explanation:
Answer: No it is not a right triangle. It is an obtuse scalene triangle.
Two plus ten times eight
(2+10)*8 = 96
Answer: Option A) x=3π/4, x=5π/4
The asymptotes of the function tan (z) are the values of z that are the odd multiples of <span>π/2:
</span>z=(2n+1)π/2, witn n= ..., -3, -2, -1, 0, 1, 2, 3, ...
In this case z=<span>2x − π, then:
</span>2x − π=(2n+1)π/2
Solving for x: Adding π both sides of the equation:
2x − π+ π=(2n+1)π/2+ π
Adding the terms on the right side of the equation:
2x=[(2n+1)π+2π]/2
Common factor π:
2x=[(2n+1)+2]π/2
2x=(2n+1+2)π/2
2x=(2n+3)π/2
Multiplying both sides of the equation by 1/2:
(1/2)(2x)=(1/2)[(2n+3)π/2]
(2/2)x=(2n+3)π/[(2)(2)]
x=(2n+3)π/4
For n=-1:
x=[2(-1)+3]π/4
x=(-2+3)π/4
x=π/4
x=π/4<π/2 No
For n=0:
x=[2(0)+3]π/4
x=(0+3)π/4
x=3π/4
π/2<x=3π/4<3π/2 Ok
For n=1:
x=[2(1)+3]π/4
x=(2+3)π/4
x=5π/4
π/2<x=5π/4<3π/2 Ok
For n=2:
x=[2(2)+3]π/4
x=(4+3)π/4
x=7π/4
x=7π/4>3π/2 No
Answer: x=3π/4, x=5π/4