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Elis [28]
3 years ago
11

99 POINTS PLZ HELP-Different shapes are drawn on cards and then the cards are placed in a bag. The number of cards for each shap

e is shown in the table.
Shape
octagon
square
circle
Number of cards
12
27
91
What is the probability that a randomly selected card has a circle drawn on it?
Enter your answer in the box.
Mathematics
2 answers:
MrMuchimi3 years ago
4 0
\frac{91}{130}
larisa86 [58]3 years ago
3 0

total number of cards: 12 + 27 + 91 = 130

total number of cards with a circle: 91

 so you have a 91/130 probability which reduces to 7/10 probability

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Answer:

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b) (2-z)/7= y/8=(x+4)/2 (option B)

Step-by-step explanation:

the parametric equation of the line passing through the point P₀= (-4,0,2) and parallel to the vector v=2i + 8j - 7k is

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or

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(2-z)/7= y/8=(x+4)/2

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3 years ago
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Find the values of x and y. <br> x + 7i = y − yi
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Answer: X = y - yi - 7i

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3 years ago
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tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

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Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

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Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

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The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

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