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ahrayia [7]
3 years ago
14

Which equation and solution can be used to solve this problem?

Mathematics
2 answers:
erastova [34]3 years ago
6 0

Answer:

Last one

Step-by-step explanation:

Let the number be q

22 less than the number: q - 22

Is 24

q - 22 = 24

q = 24 + 22

q = 46

maks197457 [2]3 years ago
4 0

Answer:

D

Step-by-step explanation:

We need to convert these words into mathematical expressions:

- "Twenty-two less than a number"; "less than" indicates that we need to use subtraction, and since it's "twenty-two less than", we have: -22. Let's say the "number" is q. Then, we have -22 of q, which is q - 22.

- "is twenty-four"; "is" in math always means "equal", so we need an equal sign with 24 next to it: = 24

Put this altogether:

q - 22 = 24

The answer is thus D.

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How much longer will it take a car traveling at an average speed for 2 miles per hour to make the trip from San francisco to New
lbvjy [14]

Answer:

1445.6 hours

Step-by-step explanation:

Distance between New York and San Francisco = 2902.8 miles (checked online)

Average speed of car = 2 mi/hr

Average speed of jet = 500 mi/hr

Time taken by Jet:

Time taken = Distance / speed

Time taken = 2902.8 / 500

Time taken = 5.8056 = 5.8 hours

Time taken by Car :

Time taken = Distance / speed

Time taken = 2902.8 / 2

Time taken = 5.8056 = 1451.4 hours

Time difference :

1451.4 - 5.8 = 1445.6 hours

7 0
2 years ago
Can you very be kind and answer
Lera25 [3.4K]

area of a circle is PI x r^2

2 = d/2 = 5.4/2 = 2.7 cm

 using 3.14 for PI

3.14 x 2.7^2 = 22.89 square inches

360 degree in a circle, shaded area is 180 degree, which is 50%

 so 22.89 x .5 = 11.45 cm^2

4 0
3 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
3 years ago
Q1 - Find the circumference of following circle. Take π = 3.14
Tanzania [10]

Answer:

The circumference of the circle is <u>C-72.22 </u><u>units</u>

Step by step explanation-

Given-

  • Diameter of circle (d) = 23 units
  • π = 3.14

Now,

<h3>\mathfrak {circumference \: of \: circle = \pi d }</h3>

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 3.14 \times 23

\:  \:  \:  \:  \:  \:  \:\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:  \boxed{  = 72.22 \: units}

6 0
2 years ago
Read 2 more answers
Can someone solve the system of equations below
KengaRu [80]
 See the attached picture:

4 0
3 years ago
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