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4 years ago

Which equation and solution can be used to solve this problem?

Mathematics

2 answers:

erastova [34]4 years ago

6 0

Answer:

Last one

Step-by-step explanation:

Let the number be q

22 less than the number: q - 22

Is 24

q - 22 = 24

q = 24 + 22

q = 46

maks197457 [2]4 years ago

4 0

Answer:

Step-by-step explanation:

We need to convert these words into mathematical expressions:

- "Twenty-two less than a number"; "less than" indicates that we need to use subtraction, and since it's "twenty-two less than", we have: -22. Let's say the "number" is q. Then, we have -22 of q, which is q - 22.

- "is twenty-four"; "is" in math always means "equal", so we need an equal sign with 24 next to it: = 24

Put this altogether:

q - 22 = 24

The answer is thus D.

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Please help! I must match the numbers on the left with all appropriate number sets on the right . A number on the left may match

Flura [38]

Answer:

$\sqrt{5}$ = Irrational

6 = Natural, Whole, Integer, Rational

$\frac{1}{2}$ = Rational

-2 = Integers, Rational

Explanation:

See attached photo! (it is hard to explain in words haha)

Side note: All natural numbers are rational numbers, but not all rational numbers are natural numbers (this applies differently to all sections, like all integers are whole, but not all whole are integers, etc)

Side note #2: Whole numbers are just natural numbers AND zero

Hope this is correct (or at least helps), have a nice day! :D

3 0

3 years ago

135°,335 Are they coterminal

DerKrebs [107]

Answer:

Step-by-step explanation:

To find coterminal angles for a given angle

add/ subtract 360° from it

Thus

135° + 360° = 495° or 135° - 360° = - 225°

3 0

4 years ago

3 1/5 ÷(z− 1/2 )=2 2/3 ÷(z+ 1/3 )

Amanda [17]

Answer

No solution for this question

Step-by-step explanation:

3 0

4 years ago

Can someone help me plss! ?

Ann [662]

Sry but that’s too much which one would you like help on

5 0

3 years ago

points C,D, and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located at (4,5), and E is located at (x,y).

kap26 [50]

Answer:

The point E is located at (9,0)

x=9, y=0

Step-by-step explanation:

we have that

Points C,D, and E are collinear on CE

Point D is between point C and point E

we know that

$CE=CD+DE$ -----> equation A (by addition segment postulate)

$\frac{CD}{DE}=\frac{3}{5}$

$CD=\frac{3}{5}DE$ ------> equation B

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance CD 

we have

C(1,8), D(4,5)

substitute in the formula

$CD=\sqrt{(5-8)^{2}+(4-1)^{2}}$

$CD=\sqrt{(-3)^{2}+(3)^{2}}$

$CD=\sqrt{18}\ units$

Find the distance DE

substitute the value of CD in the equation B and solve for DE

$\sqrt{18}=\frac{3}{5}DE$

$DE=\frac{5\sqrt{18}}{3}\ units$

Find the distance CE

$CE=CD+DE$

we have

$DE=\frac{5\sqrt{18}}{3}\ units$

$CD=\sqrt{18}\ units$

substitute the values in the equation A

$CE=\sqrt{18}+\frac{5\sqrt{18}}{3}$

$CE=\frac{8\sqrt{18}}{3}$

Applying the formula of distance CE

we have

$CE=\frac{8\sqrt{18}}{3}$

C(1,8), E(x,y)

substitute in the formula of distance

$\frac{8\sqrt{18}}{3}=\sqrt{(y-8)^{2}+(x-1)^{2}}$

squared both sides

$128=(y-8)^{2}+(x-1)^{2}$ -----> equation C

Applying the formula of distance DE

we have

$DE=\frac{5\sqrt{18}}{3}\ units$

D(4,5), E(x,y)

substitute in the formula of distance

$\frac{5\sqrt{18}}{3}=\sqrt{(y-5)^{2}+(x-4)^{2}}$

squared both sides

$50=(y-5)^{2}+(x-4)^{2}$ -----> equation D

we have the system

$128=(y-8)^{2}+(x-1)^{2}$ -----> equation C

$50=(y-5)^{2}+(x-4)^{2}$ -----> equation D

Solve the system by graphing

The intersection point both graphs is the solution of the system

The solution is the point (9,0)

therefore

The point E is located at (9,0)

see the attached figure to better understand the problem

6 0

3 years ago