Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer:
ME
Step-by-step explanation:
ME BC IMA GOD!
A system of linear inequalities in two variables consists of at least two linear inequalities in the same variables. The solution of a linear inequality is the ordered pair that is a solution to all inequalities in the system and the graph of the linear inequality is the graph of all solutions of the system.
Answer:
C. Draw a ray
Step-by-step explanation:
The first step in constructing an angle - or copying one - is to draw a ray. Then, you will use a protractor, compass, straightedge, etc.