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valentinak56 [21]
2 years ago
13

Please help I’ll give brainliest

Mathematics
2 answers:
natka813 [3]2 years ago
5 0

Answer:

<h2><em><u>-</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>18b</u></em></h2>

Step-by-step explanation:

2(a + 6b) - 3(a - 2b)

= 2a + 12b - 3a + 6b

= 2a - 3a + 12b + 6b

= <em><u>- a + 18b (Ans)</u></em>

vladimir2022 [97]2 years ago
5 0

Answer:

-a + 18b

Step-by-step explanation:

2(a + 6b) - 3(a - 2b)

Distribute the 2

2a + 12b - 3(a - 2b)

Distribute the 3

2a + 12b - 3a + 6b

Combine like terms

-a + 18b

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A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
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Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
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\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

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Step-by-step explanation:

ME BC IMA GOD!

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Answer:

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