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Arte-miy333 [17]
3 years ago
10

An infinite series is represented by:

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0
The infinite numbers is represented by D.
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Which ordered pair is the solution to the system of equations? {y=3x−102x+3y=3
uysha [10]
(3,-1) for sure i took the test 100% 
hope i helped out 
8 0
3 years ago
The five members of the Traynor family each buy train tickets. During the train ride, each family member buys a boxed lunch for
larisa [96]

Let's assume

the price of each train ticket is x

we are given

total number of family members =5

so, total cost of ticket = total number of family members*the price of each ticket

so, total cost of ticket =5*x

so, total cost of ticket =5x

now, we have

each family member buys a boxed lunch for $6.50

so, total cost of lunch box = total number of family members*price of each lunch box

so, total cost of lunch box = 5*6.50

total cost of trip = total cost of ticket+total cost of lunch box

we are given

total cost of trip is $248.50

now, we can plug values

and we get

248.50=5x+5*6.50

now, we can solve for x

248.50=5x+32.5

248.50-32.5=5x+32.5-32.5

216=5x

\frac{5x}{5} =\frac{216}{5}

x=43.2

so,

the price of each train ticket is $43.2..........Answer

8 0
3 years ago
Read 2 more answers
Maria y juan deben realizar el mapamundi en medio pliego de cartulina para la tarea de sociales pero cada uno tiene un cuarto de
kondor19780726 [428]

Answer:

Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:

  • <u>Verdadero</u>.

Step-by-step explanation:

Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:

  • Total de cartulina de María y Juan = \frac{1}{4}+\frac{1}{4}
  • Total de cartulina de María y Juan = \frac{4+4}{16}
  • Total de cartulina de María y Juan = \frac{8}{16}

Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:

  • Total de cartulina de María y Juan = \frac{4}{8}
  • Total de cartulina de María y Juan = \frac{2}{4}
  • <u><em>Total de cartulina de María y Juan = </em></u>\frac{1}{2}<u><em /></u>

Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.

3 0
3 years ago
Find the area of the regular 20​-gon with radius 77 mm.
butalik [34]
The area of a polygon equals
area = circumradius² * number of sides * sin (360 / # of sides) / 2
area = 77² * 20 * sin (360 / 20) / 2
area = 77² * 20 * sin (18) / 2
area = 118,580 * 0.30902 / 2
area = <span> <span> <span> 36,643.59 </span> </span> </span> / 2
area = 18,321.8 square millimeters


3 0
3 years ago
Please answer. Confusing me. 20 points.
Sedbober [7]
The answer is either x = -1 or x = 4.
7 0
3 years ago
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