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loris [4]
3 years ago
11

A car traveling at a certain speed will travel 76 feet per second. How many miles will the car travel in 3.1 hours if it maintai

ns the same speed? Round to the nearest tenth.
Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0
Keeping in mind that, there are 5280 feet in 1 mile, and 60 minutes in an hour and 60 seconds in each minute, thus 60*60 seconds in an hour, or 3600 seconds.

\bf \cfrac{76~\underline{feet}}{\underline{sec}}\cdot \cfrac{mile}{5280~\underline{feet}}\cdot \cfrac{3600~\underline{sec}}{hr}\implies \cfrac{76\cdot 3600~mile}{5280~hr}
\\\\\\
\cfrac{570~mile}{11~hr}\approx 51.\overline{81}\frac{mile}{hr}\\\\
-------------------------------\\\\
\textit{how many miles does it do in 3.1hrs?}\quad \cfrac{570}{11}\cdot 3.1
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I GIVE BRAINLIEST PLS HELP
ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
4 0
3 years ago
What is these decimal numbers from least to greatest
e-lub [12.9K]
Least to Greatest:
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7 0
3 years ago
Read 2 more answers
What is (14x^2– 27x+9) / (7x-3)?<br><br> A. 7x-3<br> B. 2x-3<br> C. -211x+9<br> D. 2x-33
Yakvenalex [24]

Answer:

B. 2x - 3

Step-by-step explanation:

\rm \frac{ {14x}^{2}  - 27x + 9}{7x - 3}

\rm  =  \frac{ \cancel{(7x - 3)}(2x - 3)}{ \cancel{7x - 3}}

\boxed{ \rm   \bold{= 2x - 3}}

4 0
3 years ago
Find the distance and the midpoint of the line segment with endpoints (-1,4) and (-5,3)
Marina CMI [18]

Answer:

see explanation

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1,4) and (x₂, y₂ ) = (- 5, 3)

d = \sqrt{(-5+1)^2+(3-4)^2}

  = \sqrt{(-4)^2+(-1)^2}

  = \sqrt{16+1} = \sqrt{17} ≈4.12 ( to 2 dec. places )

To find the midpoint use the midpoint formula

[0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Using the same points as above then

midpoint = [0.5(- 1- 5), 0.5(4 + 3 ) ] = [0.5(- 6), 0.5(7) ] = (- 3, 3.5 )

4 0
3 years ago
A water wheel has a radius of 4 feet and the bottom of the wheel is 1 foot from the ground. one plank is painted white and it st
Sliva [168]

The correct option is 9 feet.

The height from the ground the white plank after the motion is 9 feet.

<h3>What is rotational motion?</h3>

Anything that spins or moves in a circular route is said to be in rotational motion. It's also referred to as angular motion and circular motion. The motion can be uniform (— in other words, the velocity v remains constant) and non-uniform, but it must be circular.

Now, according to the question;

The wheel's radius is 4 feet.

The height of a bottom of a wheel from the ground equals 1 foot.

π/3 radians is the angle where the wheel is rolled.

The following relationship describes the height of a revolving wheel.

f(t) = A·sin(B·t + C) + D

Where,

D = Mid line =  4 + 1 = 5 feet

B·t = π/3

C = 0

amplitude; A = 4

Substituting the values in the function;

f(t) = 4×sin(π/3) + 5 = 8.464 ft

f(t) = 9 (approx)

Therefore, the plank's height after the /3π/3 rotation motion = 9 ft.

To know more about the rotational motion, here

brainly.com/question/2136775

#SPJ4

3 0
2 years ago
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