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harina [27]
3 years ago
14

Simplify the following using PEMDAS: [3−(3⋅3)+33÷3] × 4⋅5/10−2⋅3

Mathematics
1 answer:
kompoz [17]3 years ago
8 0

Answer: 34

Step-by-step explanation:

<u>Given expression</u>

[3 - (3 · 3) + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3

<u>Simplify by parentheses in the bracket</u>

=[3 - 9 + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3

<u>Simplify by multiplication</u>

=[3 - 9 + 33 ÷ 3] × 20 / 10 - 6

<u>Simplify by division</u>

=[3 - 9 + 11] × 10 - 6

<u>Simplify by bracket (addition/subtraction)</u>

=[-6 + 11] × 10 - 6

=[4] × 10 - 6

<u>Simplify by multiplication</u>

=40 - 6

<u>Simplify by subtraction</u>

=\boxed{34}

Hope this helps!! :)

Please let me know if you have any questions

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Hope this helps!

6 0
4 years ago
Y=2x-15 y=5x what the x equals
daser333 [38]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
G(x)=(x^2+1)(3x-5) what is the value of g(4)?
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g(x) = x^2 + 1(3x - 5)

<em><u>Replace all x's with 4.</u></em>

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g(4) = 119 (This is your answer.)

5 0
3 years ago
The measures of both
m_a_m_a [10]

Answer:

<em>m</em><em><</em><em>EAD</em><em>=</em><em>2</em><em>9</em><em>°</em>

<em>m</em><em><</em><em>CAB</em><em>=</em><em>1</em><em>1</em><em>9</em><em>°</em>

<em>Sol</em><em>ution</em><em>,</em>

<em><</em><em> </em><em>CAE</em><em>+</em><em><</em><em>EAD</em><em>+</em><em>9</em><em>0</em><em>°</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em><em>(</em><em> </em><em>angles</em><em> </em><em>on</em><em> </em><em>a</em><em> </em><em>straight</em><em> </em><em>line</em><em>)</em>

<em>6</em><em>1</em><em>+</em><em><</em><em>EAD</em><em>+</em><em>9</em><em>0</em><em>°</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em>

<em><</em><em>EAD</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>(</em><em>9</em><em>0</em><em>+</em><em>6</em><em>1</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>1</em><em>5</em><em>1</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>9</em><em>°</em>

<em><</em><em>CAB</em><em>+</em><em><</em><em>FAB</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em><em>(</em><em> </em><em>Linear pair</em><em>)</em>

<em><</em><em>CAB</em><em>+</em><em>6</em><em>1</em><em>°</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em>

<em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em><em>°</em><em>-</em><em>6</em><em>1</em><em>°</em>

<em><</em><em>CAB</em><em>=</em><em>1</em><em>1</em><em>9</em><em>°</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

3 0
4 years ago
(PLZ HELP STAT) The lengths of three sides of a trapezoid are shown below:
balandron [24]
Hey there :)

The perimeter formula of a trapezium is:
P = a + b + c + d ( adding all sides )

Perimeter is given : P = 17z³ + 60z² + 2z - 5

Part A :

Total lengths of sides 1, 2 and 3 will be just adding the given lengths : 
1 → 16z² - 4z + 2
2 → 7z² - 2z + 21
3 → 18z² - 3z + 2

side 1 + side 2 + side 3
( 16z² - 4z + 2 ) + ( 7z² - 2z + 21 ) + ( 18z² - 3z + 2 )

Combine like terms together:

16z² + 7z² + 18z² - 4z - 2z - 3z + 2 +21 + 2
41z² - 9z + 25

Part B:

Length of 4th side will be the total perimeter minus the total length of sides 1, 2 and 3:

( 17z³ + 60z² + 2z - 5 ) - ( 41z² - 9z + 25 )

Combine like terms

17z³ + 60z² - 41z² + 2z + 9z - 5 - 25
17z³ + 19z² + 11z - 30

Part C:

Addition of polynomials result in polynomials as well as subtraction of polynomials result in polynomials.

Therefore, this polynomial is closed under addition and subtraction. 

3 0
3 years ago
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