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Dmitry_Shevchenko [17]
3 years ago
7

2z+4≤−2 interval notation

Mathematics
2 answers:
Leni [432]3 years ago
4 0

Good morning ☕️

Answer:

<h2>(-∞ , -3]</h2>

Step-by-step explanation:

NOTE:__________________________________________________

in order to solve inequality like this we need to isolate the variable z and that’s what we will do in the next few steps___________________

<u><em>>step 1:</em></u> <u><em>subtract 4 from both sides </em></u>

2z+4\leq -2\\\\means\\\\2z\leq -2-4\\\\then\\\\2z\leq-6

<u><em>>step 2: </em></u><u><em>divide both sides by 2</em></u>

2z\leq-6\\\\then\\\\z\leq-3

<u><em>>Interval notation : </em></u>

(-∞ , -3]

:)

JulijaS [17]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Given

2z + 4 ≤ - 2 ( subtract 4 from both sides )

2z ≤ - 6 ( divide both sides by 2 )

z ≤ - 3

solution is x ∈ ( - ∞, - 3 ]

The parenthesis on the left means that x cannot equal - ∞

The ] on the right means that x can equal - 3

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2. If g(x) = x2 – 3x + 2, find g(-4).
juin [17]

42

Step-by-step explanation:

you plug in -4 into x and multiply

ex: (-4)2-3(-4)+2

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4 years ago
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A triangle is inscribed inside another triangle . the base of the interior triangle is 9cm. what is the area of the shaded regio
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Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi
Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ;  2Bs and 3Cs it is possible to get a palindrome if you fixed the  letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

<u>C</u> (       ) <u>C</u> (       ) <u>C</u>

To fill in the gaps we have  4 letters  A and 2 letters B, wich we have two divide in two palindrome gaps,  

AAB         and    BAA the palindrome is  C  AAB C BAA C

BAA         and    AAB    "           "           is  C  BAA C AAB C  

ABA         and    ABA    "           "           is  C  ABA C ABA C

b) 4 A  ;   2B  ; 3C

We have the total number of elements  9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A  ; 2 B  ; 2C  : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

5 0
3 years ago
Graph the functions on the same coordinate axis. {f(x)=−2x+1g(x)=x2−2x−3
NikAS [45]

Answer:

(2,-3) and (-2,5)

Step-by-step explanation:

Let us graph the two equations one by one.

1. f(x)=-2x+1

If we compare this equation with the slope intercept form of a line which is given as

y=mx+c

we see that m = -1 and c =1

Hence the slope of the line is -2 and the y intercept is 1. Hence one point through which it is passing is (0,1) .

Let us find another point by putting x = 1 and solving it for y

y=-2(1)+1

y=-2+1 = -1

Let us find another point by putting x = 2 and solving it for y

y=-2(2)+1

y=-4+1 = -3

Hence the another point will be (2,-3)

Let us find another point by putting x = -2 and solving it for y

y=-2(-2)+1

y=+1 = 5

Hence the another point will be (-2,5)

Now we have two points (0,1) ,(1,-1) ,  (2,-3) and (-2,5) we joint them on line to obtain our line  

2.

g(x)=y=x^2-2x-3

y=x^2-2x+1-1-3

y=(x-1)^2-4

(y+4)=(x-1)^2

It represents the parabola opening upward with vertices (1,-4)

Let us mark few coordinates so that we may graph the parabola.

i) x=0 ; y=y=(0)^2-2(0)-3=0-0-3=-3 ; (0,-3)

ii)x=-1 ; y=(-1)^2-2(-1)-3=1+2-3=0 ; (-1,0)

iii) x=2 ; y=(2)^2-2(2)-3 = 4-4-3 =-3 ;(2,-3)

iii) x=1 ; y=(1)^2-2(1)-3 = 1-2-3 =-4  ;(1,-4)

iii) x=-2 ; y=(-2)^2-2(-2)-3 = 4+4-3 =5  ;(-2,5)

Now we plot them on coordinate axis and line them to form our parabola

When we plot them we see that we have two coordinates (2,-3) and (-2,5) are common , on which our graphs are intersecting. These coordinates are solution to the two graphs.

3 0
4 years ago
Find the constant of variation k for the direct variation.
slega [8]

Answer:

K = -2

Step-by-step explanation:

If y varies directly as x, k (constant) can be found by dividing the y-coordinate by the x-coordinate.

k = \frac{2}{-1} = -2

4 0
3 years ago
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