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3 years ago

Write a quadratic equation that has x-intercepts of -1/3 and 5/2

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

<h2>Answer: $6x^{2}-13x-5$ </h2>

Step-by-step explanation:

Given that the two roots of the quadratic equation are $\frac{-1}{3}$ and $\frac{5}{2}$ .

If $\alpha$ $,\beta$ are the roots of the quadratic equation,the equation is $(x-\alpha )(x-\beta )$ .

It is given that $\alpha =\frac{-1}{3}$ and $\beta =\frac{5}{2}$ .

So,the equation is

$(x-(\frac{-1}{3}))(x-\frac{5}{2})$

= $x^{2}-\frac{5}{2}x+\frac{x}{3}-\frac{5}{6}$

= $6x^{2}-13x-5$

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Short Answer
2x^3+7x^2+3x-2

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3.)9x-6x=3x

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3 years ago

A farmer wants to estimate the average growth in height of his corn plants over a two week period

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Answer:How much does he usually grow ?

Step-by-step explanation:

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4 years ago

How do I solve for d in the following equation? c(ad) + x= bd + ad(yz)

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3 years ago

Read 2 more answers

A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0

3 years ago

the sum of age of mabel and fred is 38 years,four years ago the age of mabel was the square of Fred age.Find their ages

Andrej [43]

m+f=38

(f-4)^2=m-4

f^2=m IF their age is 30 combined

4^2=16

16=16

Fred is 4, Mabel is 16.

8 0

3 years ago