Question

Write a quadratic equation that has x-intercepts of -1/3 and 5/2

Answer 1

Answer:$6x^{2}-13x-5$

Step-by-step explanation:

Given that the two roots of the quadratic equation are $\frac{-1}{3}$ and $\frac{5}{2}$.

If $\alpha$$,\beta$ are the roots of the quadratic equation,the equation is $(x-\alpha )(x-\beta )$.

It is given that $\alpha =\frac{-1}{3}$ and $\beta =\frac{5}{2}$.

So,the equation is

$(x-(\frac{-1}{3}))(x-\frac{5}{2})$

=$x^{2}-\frac{5}{2}x+\frac{x}{3}-\frac{5}{6}$

=$6x^{2}-13x-5$