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Rashid [163]
3 years ago
12

Find the greatest common factor of 10, 30 and 45

Mathematics
1 answer:
lawyer [7]3 years ago
5 0

Answer:

The greatest common factor is 5.

Step-by-step explanation:

The prime factorisation of 10, 30 and 45 is,

10 = 2 × 5

30 = 2 × 3 × 5

45 = 3 × 3 × 5

The prime factor '5' is common in the factorisation of 10, 30 and 45

So, the greatest common factor of 10, 30 and 45 is 5.

You might be interested in
. Ethan's favorite kind of exercise is running. He runs on a path that is 1.75 miles long. Last week, Ethan ran on the path 6 ti
Talja [164]

Answer:

10.5 miles

Step-by-step explanation:

Ethan's favorite kind of exercise is running. He runs on a path that is 1.75 miles long. Last week, Ethan ran on the path 6 times.

The number of miles that Ethan ran on the path last week is calculated as:

Number of miles × Number of times he ran

= 1.75 miles × 6 times

= 10.5 miles

Therefore, the number of miles that Ethan ran on the path last week is 10.5 miles

6 0
3 years ago
Solve sint = cos2t, for –4π ≤ t ≤ –2π
e-lub [12.9K]

Answer:

-(23/6)π

-(19/6)π

-3π

Step-by-step explanation:

cos2t=cos^2t-sin^2t => cos^2t=1-sin^2t =>cos2t=1-2sin^2t

sint=1-2sin^2t, if x=sint, thenn we have 2x^2+x-1=0

Here x=0.5, x=-1, as x=sint => sint = -1 solutions for -4π to -2π is t=-3π,

sint = 0.5 solutions for -4π to -2π is t= -(23/6)*π, and t = -(19/6)*π

3 0
3 years ago
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 180180 engin
tiny-mole [99]

Answer:

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.6 represent the sample mean

\sigma=0.9 represent the population standard deviation

n=180 sample size  

\mu_o =4.8 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if thetrue mean is below the specifications, the system of hypothesis would be:  

Null hypothesis:\mu \geq 4.8  

Alternative hypothesis:\mu < 4.8  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

P-value

Since is a one sided test the p value would be:  

p_v =P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

4 0
3 years ago
Subtract the following. Write your answer in standard notation . 18-9.2×10^-4
puteri [66]

Answer:1.799908×10^1

Step-by-step explanation:

18-0.00092

=17.99908

In standard form=1.799908×10^1

8 0
3 years ago
If I had 22 apples and someone stole 5. How many would that person have?
Sunny_sXe [5.5K]
That person, the someone, would have the 5 that they stole

hope this helps ;)
3 0
3 years ago
Read 2 more answers
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