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Alex777 [14]
3 years ago
15

Erin caught 8 more fish than Juan caught

Mathematics
1 answer:
Gennadij [26K]3 years ago
7 0

Answer:

Second option: Equation, because 8 plus the fish that Juan caught equals  the fish that Erin caught

Step-by-step explanation:

You can for sure make an equation, all you need is to have variables and that's allowed in this case.

E=J+8

E=Erin J=Juan

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the value of c(30) is 21.2, which represents the customers final cost of $21.20

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4 0
3 years ago
The owners of the pet sitting business have set aside $48 to purchase chewy toys for dogs, 2,
Contact [7]

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more angles and variables.

Let x represent the number of dogs and y represent the number of cats collars. Hence:

At Marco's market:

2x + 6y = 48 (1)

At Sonia's superstore:

4x + 4y = 48  (2)

Graphing both equations, the solution is at (6,6)

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

Find out more on Equation at: brainly.com/question/13763238

7 0
2 years ago
-8.1 irrational number or rational
Luda [366]

Answer:

Rational

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
What number must you add to complete the square?<br> x^2 + 2x = -1
Andru [333]
\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

6 0
3 years ago
Read 2 more answers
Solve the following exponent:<br><br> 70
Alika [10]

Answer  70 = 7070

Step-by-step explanation: denotes how many times to multiply the base (70)

7 0
1 year ago
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