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3 years ago

Erin caught 8 more fish than Juan caught

Mathematics

1 answer:

Gennadij [26K]3 years ago

7 0

Answer:

Second option: Equation, because 8 plus the fish that Juan caught equals the fish that Erin caught

Step-by-step explanation:

You can for sure make an equation, all you need is to have variables and that's allowed in this case.

E=J+8

E=Erin J=Juan

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3 years ago

The owners of the pet sitting business have set aside $48 to purchase chewy toys for dogs, 2,

Contact [7]

6 chewy toys and 6 cat collars are needed to have the same amount or price at both stores.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more angles and variables.

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At Marco's market:

2x + 6y = 48 (1)

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2 years ago

-8.1 irrational number or rational

Luda [366]

Answer:

Rational

Step-by-step explanation:

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3 years ago

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What number must you add to complete the square?<br> x^2 + 2x = -1

Andru [333]

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$\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}$

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$\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}$

If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

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Alika [10]

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