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miv72 [106K]
3 years ago
15

The probability that an international flight leaving the United States is delayed in departing (event D) is .26. The probability

that an international flight leaving the United States is a transpacific flight (event P) is .50. The probability that an international flight leaving the U.S. is a transpacific flight and is delayed in departing is .13.
what is the probability?​
Mathematics
1 answer:
Paladinen [302]3 years ago
3 0

Missing part:

What is the probability that an international flight leaving the US is delayed in departing given that the flight is a transpacific flight?  

Answer:

P(D|P) = 0.50

Step-by-step explanation:

Given

P(D) = 0.26

P(P) = 0.50

P(D\ and\ P) = 0.13

The question illustrates conditional probability and it is represented as:

P(D|P)

This is then calculated as:

P(D|P) = \frac{P(D\ and\ P)}{P(D)}

So, we have:

P(D|P) = \frac{0.13}{0.26}

P(D|P) = 0.50

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Which expression simplifies to 41? Choose all that apply!
Arada [10]

Answer:

None of the expressions is simplified to 41.

Step-by-step explanation:

You have to follow the P.E.M.D.A.S., this is:

P:Parentheses first.

E:Exponent next.

M:Multiplication.

D:Division.

(Multiplication and Division is whichever come first, from left to right)

A: Addition.

S: Subtraction.

(Addition and Subtraction is whichever come first, from left to right).

<u><em>We are going to analyze every option:</em></u>

1. 10+ 2.4 - 1

First we have to solve the multiplication:

10+ 2.4 - 1=10+8-1

Now we have to solve the addition and subtraction from left to right:

10+8-1=18-1=17\neq 41

This is not a correct answer.

2. 10+2.(4-1)

We have to solve the parentheses first:

10+2.(4-1)=10+2.(3)

Now the multiplication and then the addition.

10+2.(3)=10+6=16\neq 41

This is not a correct answer.

3. (10+23).4-1

We have to solve the parentheses first:

(10+23).4-1=(33).4-1

Now the multiplication and then the subtraction:

(33).4-1=132-1=131\neq 41

This is not a correct option.

4. 10+(2^2.4)-1

We have to solve the parentheses first, in the parenthesis first we have to solve: 2^2 and then do the multiplication.

10+(2^2.4)-1=10+(4.4)-1=10+16-1

Now we have to solve the addition and subtraction from left to right:

10+16-1=26-1=25\neq 41

This expression is not a correct option.

Then none of the expressions is simplified to 41.

5 0
3 years ago
Round 0.83,to the nearest thousandths<br> NEED HELP IMMEDIATELY!!!
Dafna1 [17]
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3 years ago
Lupe can ride her bike at a rate of 20 mph when there is no wind. On one particular day, she rode 2 miles against the wind and n
lana [24]
Let wind speed = x mph 

when she rode 2 miles against the wind we have:-
speed = distance / time so
20 - x  = 2 / t -------(1)      where t is the time she took.

when riding with the wind we have 

20 + x = 3 / t--------(2)   adding equations (1) and (2):-

40  =  2/t + 3/t
40 =  5/t
t = 5/40 = 1/8 hr 

x = 20 - 2 / 1/8  = 20 - 16 = 4

Wind speed was 4 mph Answer

4 0
3 years ago
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A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

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Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

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Likurg_2 [28]
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