Question

What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over 3?

Answer 1

$\frac{x+6}{x+4} +\frac{x-3}{3}$

make denomenators the same

we have
x+4 and 3
times the fraction with x+4 in denomenator with the fraction 3/3
times the fraction with 3 in denomenator with the fraction x+4
we get
$\frac{3x+18}{3x+12} +\frac{x^2+x-12}{3x+12}$
since common denoms, can add them to get
$\frac{3x+18+x^2+x-12}{3x+12}$
$\frac{x^2+4x+6}{3x+12}$
that is simplified