HELP! I really have no clue how to do this problem. Please help!

Select the correct answer from each drop-down menu. In the figure, . Angles are congruent . ∠GAC ≅ ∠AFE because they are corresp

Hoochie [10]

Answer:

∠GAC ≅ ∠HFD by the Property of Congruence.

Step-by-step explanation:

I'm going to be honest the question is a little confusing cause of the beginning, but if you're looking for which angles are actually congruent it's ∠GAC ≅ ∠HFD

8 0

3 years ago

Someone get me the answers ASAP!! thank you

Virty [35]

This relies on the distance formula like number two, which you answered correctly.

I think it's helpful to draw this out. I made a digital drawing on GeoGebra (free) and connected the vertices. Now, to find the area, we need the side lengths to start. This program actually gives you the side lengths as well, but pretending we don't already have that, you can plug in each vertex into the distance formula.

$a = \sqrt{(-4-3)^{2}+ (2-2)^{2}} = 7$

$b = \sqrt{(3-3)^{2}+(2-(-5))^{2}} = 7$

$c = \sqrt{(3-(-4))^{2}+(-5-(-2))^{2}} = \sqrt{58}$

$d = \sqrt{(-4-(-4))^{2}+(2-(-2))^{2}} = 4$

So, unfortunately, we don't have a regular polygon, so this isn't simply length times width. But we can easily cut this into a rectangle and a triangle, whose areas are much easier to find (see second image).

The area, A, of a triangle is $\frac{1}{2} B * h$ and the area of a rectangle is simply $l * w$ . So the base of our triangle is 7 units, and the height is 3 units, so the area is 10.5 units squared. The length of our rectangle is 7 units, and the width is 4 units, so the area is 28 units squared.

$A = A_{triangle} + A_{rectangle} = 10 \frac{1}{2}+28 = 38\frac{1}{2}$ units squared.

I would like to clarify that you do not actually need to find all those distances for this problem. Once it's drawn out, it's fairly easy to tell.