The answer is : ![\left(m+n^2\right)\left(m-n^2\right)](https://tex.z-dn.net/?f=%5Cleft%28m%2Bn%5E2%5Cright%29%5Cleft%28m-n%5E2%5Cright%29)
Here are the steps below to help you! ^^
The answer to the above equation is 3
Step-by-step explanation:
(a-b)³+(b-c)³+(c-a)³: (a-b)(b-c)(c-a)
Let us consider (a−b)= x, (b−c)= y and (c−a)= z.
Hence, It is obvious that:
x+y+z =0 ∵all the terms gets cancelled out
⇒We must remember the algebraic formula
x³+y³+z³−3xyz= (x+y+z) (x²+y²+z²-xy-xz-yz)
Since x+y+z=0 ⇒Whole “(x+y+z) (x²+y²+z²-xy-xz-yz)
” term becomes 0
x³+y³+z³−3xyz =0
Alternatively, x³+y³+z³= 3xyz
Now putting the value of x, y, z in the original equation
(a-b)³+(b-c)³+(c-a)³ can be written as 3(a-b)(b-c)(c-a) since (a−b)= x, (b−c)= y and (c−a)= z.
3(a-b)(b-c)(c-a): (a-b)(b-c)(c-a)
= 3 ∵Common factor (a-b)(b-c)(c-a) gets cancelled out
Answer to the above question is 3
Answer:
Always Irrational
Step-by-step explanation:
An Irrational number is described as a number which cannot in the actual sense be expressed as a ratio between two integers and is not an imaginary number. It means that an irrational number cannot be expressed as a simple fraction.
If written in decimal notation, an irrational number would have an infinite number of digits to the right of the decimal point, without repetition. Hence irrational numbers are floating point numbers.
The quotient of a rational number and an irrational number is always irrational.
Answer:
77 boxes
Step-by-step explanation:
1000/13= 76.9230769
They can't sell part of a box and a little extra money never hurt any one.