All categories

3 years ago

Evaluate f(x+3) when f(x)=-x^2-2x+2

Mathematics

1 answer:

ziro4ka [17]3 years ago

3 0

Answer:

f(x + 3) = -x² - 8x - 13

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation
Expanding
Terms/Coefficients/Degrees

Step-by-step explanation:

Step 1: Define

f(x) = -x² - 2x + 2

f(x + 3) is x = x + 3

Step 2: Find

Substitute in x: f(x + 3) = -(x + 3)² - 2(x + 3) + 2
Expand: f(x + 3) = -(x² + 6x + 9) - 2x - 6 + 2
Distribute -1: f(x + 3) = -x² - 6x - 9 - 2x - 6 + 2
Combine like terms: f(x + 3) = -x² - 8x - 13

You might be interested in

Please help with via math I suck at math so plz help... will give brainiest to the person I think gave the best answer.

irga5000 [103]

4:3 for the ratio and for the word ratio you can say that there is 4 squares and 3 triangles

6 0

3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

3 years ago

Can someone help me?

mart [117]

-2 + 8 = 6

because if you have 2 negative circles ●● and 8 positive circles ○○○○○○○○ then once you take away the first two circles you get you answer. You do the opposite. :) ( hope that make sense... )