Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
I do not understand what to do , more explicitly sorry :(
The second term of the given sequence aₙ = -5(n² + 1n) when solved gives us; a₂ = -20
<h3>How to find the nth term of a sequence?</h3>
We are given the formula for a sequence as;
aₙ = -5(n² + 1n)
Where n is the position of the term.
Now, for the first term, we will have;
a₁ = -5(1² + 1(1))
a₁ = -10
The second term of the sequence is;
a₂ = -5(2² + 1(2))
a₂ = -20
Read more about Sequence at; brainly.com/question/6561461
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Given:
LMN is an equilateral triangle.
LM = LN = MN = 12 cm
To find:
The height of the triangle h.
Solution:
In a right angle triangle,
Multiply both sides by 12.
Therefore, the height of the triangle is 
cm.
