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ANTONII [103]
3 years ago
15

Approximately how many times greater is 8.5×108 than 3.4×105 ? A 2.5 B 250 C 2,500 D 25,000

Mathematics
2 answers:
zlopas [31]3 years ago
5 0
It is a<span>pproximately 2.5 times greater</span>
Vlada [557]3 years ago
3 0

Solution:

we have been asked to find that , how many times one number is to the other given numbers.

To do this we will divide the larger number by the smaller number and the resulting number will be the answer of the question.

Here the larger number is 8.5\times10^8

The smaller number is 3.4\times 10^5

Now lets divide as follows

\frac{8.5\times10^8}{3.4\times 10^5} =\frac{8.5}{3.4}\times 10^{8-5}\\ \\\frac{8.5\times10^8}{3.4\times 10^5} =2.5\times10^3=2500

Hence the correct option is C.

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Explain how to write 45,100,000 in scientific notation.
Komok [63]

Step-by-step explanation:

45,100,000  \\  = 4.51 \times  {10}^{7}

5 0
3 years ago
Dan has twice as many stickers as cam does. If Dan gives cam 15 of his stickers he will have 22 more than cam. How many stickers
sleet_krkn [62]
I’m not very sure but it might be 74 because if you add 15 to 22 you get 37 and 37 x 2= 72..? sorry if i’m wrong :(
7 0
2 years ago
The amount that results when $4,000 is compounded at 6% annually over seven years.
dimulka [17.4K]
The formula is
A=p (1+r)^t
A future value?
P present value 4000
R interest rate 0.06
T time 7 years
A=4,000×(1+0.06)^(7)
A=6,014.52

Interest earned=A-p
6,014.52−4,000=2,014.52

Hope it helps!
8 0
3 years ago
I promise I WILL MARK YOU AS BRAINLIEST How many minutes is it before 12 noon if nine minutes ago it was twice as
Snowcat [4.5K]

Answer:

120 - x - 9 past 10am

Step-by-step explanation:

Call “x” the number of minutes it is before 12 noon. Measure time in minutes from 10am, so that 12 noon is 2*60 = 120 minutes after 10 am. The current time is 120 - x after 10 am. Nine minutes ago it was 120 - x - 9 past 10am.

7 0
3 years ago
Read 2 more answers
In matrix multiplication, such as AB=C, the columns of B form the rows of C. why is this?
Gnesinka [82]
Let's work with 2-by-2 matrices so we're on the same page. The ideas will work for any appropriate matrices.

From the rule of matrix multiplication, we see:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right] = \left[\begin{array}{cc} a_{11}b_{11} + a_{12}b_{21} & a_{11}b_{12} + a_{12}b_{22} \\ a_{21}b_{11} + a_{22}b_{21} & a_{21}b_{12} + a_{22} b_{22} \end{array}\right]
As you noted, we see the columns of B contributing to the rows of C. The question is, why would we ever have defined matrix multiplication this way?

Here's a nontraditional way of feeling this connection. We can define matrix multiplication as "adding multiplication tables." A multiplication table is made by starting with a column and a row. For example,
\begin{array}{ccc} {} & 1 & 2 \\ 1 & {} & {} \\ 2 & {} & {} \end{array}
We then fill this table in by multiplying the row and column entries:
\begin{array}{ccc} {} & [1] & [2] \\ 1| &1 & 2 \\ 2| & 2 &4 \end{array}
It's then reasonable to say that given two matrices A and B, we can construct multiplication tables by taking the columns of A and pairing them with the rows of B:
\left[\begin{array}{cc}a_{11} & a_{12} \\a_{21} & a_{22} \end{array}\right] \left[\begin{array}{cc}b_{11} & b_{12} \\b_{21} & b_{22} \end{array}\right]

= \begin{array}{cc} {} & \left[\begin{array}{cc} b_{11} & b_{12}\end{array} \right]\\ \left[\begin{array}{c} a_{11} \\ a_{21} \end{array} \right] \end{array} +\begin{array}{cc} {} & \left[\begin{array}{cc} b_{21} & b_{22}\end{array} \right]\\ \left[\begin{array}{c} a_{12} \\ a_{22} \end{array} \right] \end{array}

= \left[\begin{array}{cc} a_{11} b_{11} & a_{11} b_{12} \\ a_{21} b_{11} & a_{21} b_{12} \end{array} \right] + \left[\begin{array}{cc} a_{12} b_{21} & a_{12} b_{22} \\ a_{22} b_{21} & a_{22} b_{22} \end{array} \right]

Adding these matrices together, we get the exact same expression as the traditional definition. 




5 0
3 years ago
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