All categories

3 years ago

5x+3x=5x+15/2 what value 3x make the equation true

2 answers:

andrey2020 [161]3 years ago

4 0

Subtract 5x from both sides. You'll get 3x=15/2
Turn 15/2 into a mixed number. 7 1/2
Divide 3 both sides.
Answer: 2 1/2

Check your work.

5*2 1/2 =12.5 3*2 1/2= 7.5
Therefore 12.5+7.5=12.5+7.5
12.5+7.5=20
Therefore the answer is 2.5 or 2 1/2

Dovator [93]3 years ago

4 0

We need to get the 3x alone so
5X+3X=5X+15÷2
(÷5x)3X=5X+7.5(÷5X)
(÷3)X=7.5(÷3)
X=7.5÷3
X=2.s<u />

You might be interested in

A room has a cathedral ceiling. If the walls in the room are 10 feet high and the ceiling is 18 feet high in the center of the r

9966 [12]

Check the picture below

notice, the run is half 35

recall slope = rise/run

4 0

3 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust

Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

$321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320$

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}$

STEP 3: Calculate the mean

$\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}$

STEP 4: Calculate the Standard deviation

$\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\ \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\ \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}$

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

$\begin{gathered} \text{IQR}=Q_3-Q_1 \\ \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\ \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}$

STEP 6: Find the Interquartile Range

$\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}$

Hence, the interquartile range of the data is 116

3 0

1 year ago

Nothing that 5 miles is equal to 8 kilometers. Convert 20 miles to kilometers.

adell [148]

The correct answer is 32 kilometers.

3 0

3 years ago

the difference between 2 whole number is 66 the ratio of the 2 whole number is 2.5 what are the two numbers

ch4aika [34]

Given :difference between 2 whole number = 66ratio of the 2 whole number =2:5Let:1 whole number be 2x2 whole number be 5xA/Q

difference between 2 whole number = 66

Let's turn it into algebraic equation:

5x - 2x = 663x= 66x =66 /3x =22

Now Let's put value of x to find two whole numbers

Finaly :1 whole number = 2x1 whole number = 2×221 whole number =44

2 whole number = 5x2 whole number = 5×222 whole number = 110

3 0

2 years ago

. The new saleswoman at Clocks Unlimited was very good. During her first day on the job she sold at least two of each of the thr

LiRa [457]

Answer:

Step-by-step explanation:

Let the number of the kitchen clock sold =a

Let the number of the cuckoo clock sold =b

Let the number of the two-foot high grandfather clocks sold =c

The new saleswoman sold at least two of each of the three models.

Therefore:

$a\geq 2\\b \geq 2\\c \geq 2$

In all, she collected $300 from selling these models alone

17a+31b+61c=300

17(2)+31(2)+61(2)=218

300-218=82

Next, we try to express the remainder (82) in terms of 17, 31 and 61

82=17(3)+31

Therefore, she sold:

5 kitchen clocks
3 cuckoo clocks
2 two-foot high grandfather clocks

She sold 5 $17 clocks.

CHECK:

17(5)+31(3)+2(61)=$300

4 0

3 years ago