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3 years ago

15

The vocab word for the inside of a 2D figure

2 answers:

Leviafan [203]3 years ago

5 0

Area is t<span>he square units inside a 2D figure</span>

jasenka [17]3 years ago

3 0

Area is the vocab word hope this helps! :D

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Sin∅=√3-1/2 find approximate value of sec∅(sec∅+tan∅)/1+tan²∅

Neko [114]

Answer:

The approximate value of $f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}$ is 1.366.

Step-by-step explanation:

Let $f(\theta) = \frac{\sec \theta \cdot (\sec \theta+\tan \theta)}{1+\tan^{2}\theta}$ , we proceed to simplify the formula until a form based exclusively in sines and cosines is found. From Trigonometry, we shall use the following identities:

$\sec \theta = \frac{1}{\cos \theta}$ (1)

$\tan\theta = \frac{\sin\theta}{\cos \theta}$ (2)

$\cos^{2}+\sin^{2} = 1$ (3)

Then, we simplify the given formula:

$f(\theta) = \frac{\left(\frac{1}{\cos \theta} \right)\cdot \left(\frac{1}{\cos \theta}+\frac{\sin \theta}{\cos \theta}\right) }{1+\frac{\sin^{2}\theta}{\cos^{2}\theta} }$

$f(\theta) = \frac{\left(\frac{1}{\cos^{2} \theta} \right)\cdot (1+\sin \theta)}{\frac{\sin^{2}\theta + \cos^2{\theta}}{\cos^{2}\theta} }$

$f(\theta) = \frac{\left(\frac{1}{\cos^{2}\theta}\right)\cdot (1+\sin \theta)}{\frac{1}{\cos^{2}\theta} }$

$f(\theta) = 1+\sin \theta$

If we know that $\sin \theta =\frac{\sqrt{3}-1}{2}$ , then the approximate value of the given function is:

$f(\theta) = 1 +\frac{\sqrt{3}-1}{2}$

$f(\theta) = \frac{\sqrt{3}+1}{2}$

$f(\theta) \approx 1.366$

5 0

3 years ago

Add the two expressions:

Korvikt [17]

(-6.3x + 4) + (1.5x - 6)

-6.3x + 1.5x = -4.8x
4 + (-6) = -2

-4.8x - 2 is your answer

hope this helps

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3 years ago

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Rosa works in an office building with many floors. for her office, she goes down 2 floors for a meeting. then, she goes up 7 flo

Pachacha [2.7K]

It is in the 10th floor

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3 years ago

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Solve for w 3w + 6w - 19 = -91<br> please

3241004551 [841]

Hi ;-)

$3w+6w-19=-91\\\\3w+6w=-91+19\\\\9w=-72 \ \ /:9\\\\\huge\boxed{x=-8}$

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3 years ago

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Describe the graph of y = negative x squared and compare it with the graph of y = x squared.

levacccp [35]

Answer:

The graph of the first equation opens downward while the graph of the second equation opens upward. Both graphs are parabolas that pass through 0,0.

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3 years ago