The 1st term is 60.
Add 50 to this to get the 2nd term, 60 + 50 = 110.
Add 50 to that to get the 3rd term, 110 + 50 = 160.
Add 50 to that to get the 4th term, 160 + 50 = 210.
And so on...
Notice that in the 2nd term, we added 1 copy of 50 to the 1st term.
In the 3rd, we ultimately added 2 copies of 50 to the 1st term.
In the 4th, we added 3 50s.
And so on... If the pattern continues, then the <em>n</em>-th term can be obtained by adding (<em>n</em> - 1) copies of 50 to the first term.
So, the 100th term is
60 + (100 - 1) * 50 = 5010
3x - 9y = 9
-3x + 4y = -14
-5y = -5
y = 1
3x - 9(1) = 9
3x - 9 = 9
3x = 18
x = 6
So, the answer is (6, 1)
30b+3= s
It would be thirty students times the number of buses, with an addition of 3 students equal to the total number of students when on the field trip.
I hope this helps!
~cupcake
These problems are based on the Pythagorean Theorem. The Pythagorean Theorem is a^2 + b^2 = c^2. If the two sides are equal, the triangle is a right triangle. If c^2 is less, the triangle is acute. If c^2 is more, the triangle is obtuse.
Obtuse: c^2 > a^2 + b^2
Acute: c^2 < a^2 + b^2
Right: c^2 = a^2 + b^2
#7 --- Obtuse
21^2 ___ 8^2 + 15^2
441 ___ 64 + 225
441 > 289
#8 --- Right
20^2 ___ 12^2 + 16^2
400 ___ 144 + 256
400 = 400
#9 --- Acute
6^2 ___ 4^2 + 5^2
36 ___ 16 + 25
36 < 41
Hope this helps!
