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2 years ago

13

Why is the lady’s shadow in the picture not a rigid transformation?

1 answer:

Eva8 [605]2 years ago

5 0

Answer:

The shadow is not the same image as the lady

Step-by-step explanation:

Had it in a test got it right

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What is x^4-4x^3-32 in factored form

marishachu [46]

Factoring: x4-4x3+8x-32

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 8x-32
Group 2: -4x3+x4

Pull out from each group separately :

Group 1: (x-4) • (8)
Group 2: (x-4) • (x3)
-------------------
Add up the two groups :
(x-4) • (x3+8)

3 0

2 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

lyudmila [28]

x=-9-4y

substitute

2(-9-4y)+5y=-6

-18-8y+5y=-6

-18-3y=-6

-3y=-6+18

-3y=12

-3y÷-3= 12÷-3

y=-4

4 0

3 years ago

Find the length of the unknown side. Round your answer to the nearest whole number. (4 points)

balu736 [363]

Answer: 14 meters

Step-by-step explanation:

Use the pythagorean theorem to solve.

12 ² + 8 ²= c ²

208= c ²

√ 208 = √ c ²

14.42= c

14 meters

5 0

2 years ago

Read 2 more answers

A television sports commentator wants to estimate the proportion of citizens who "follow professional football."

Angelina_Jolie [31]

Answer: a)2206 b) 2209

Step-by-step explanation:

Formula to find the sample size :

a) If prior population proportion (p) is known.

$n=p(1-p)(\dfrac{z_{c}}{E})^2$

b) If prior population proportion (p) is unknown.

$n=0.25(\dfrac{z_{c}}{E})^2$

where, ${z_{c}$ is the z-value associated with confidence level and E would be the margin of error .

Solution : Let p be the proportion of citizens who "follow professional football."

a) Given : p=0.48

Margin of error : E= 0.02

z-value for 94% confidence = $z_c=1.88$

Required sample size would be :

$n=p(1-p)(\dfrac{z_{c}}{E})^2$

$\Rightarrow\ n=0.48(1-0.48)(\dfrac{1.88}{0.02})^2$

Simply ,

$n=2205.4656\approx2206$ [Rounded to the next whole number.]

∴ The sample size is <u>2206</u>.

b) Proportion of citizens who "follow professional football" is unknown.

Margin of error : E= 0.02

z-value for 94% confidence = $z_c=1.88$

Required sample size would be :

$n=0.25(\dfrac{z_{c}}{E})^2$

$\Rightarrow\ n=0.25(\dfrac{1.88}{0.02})^2$

Simply ,

$n=2209$

∴ The sample size is <u>2209</u>.

8 0

3 years ago

Help any one please?

AfilCa [17]

A = (1/2)(8yd)(15yd) = 60 yd²

5 0

3 years ago