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choli [55]
3 years ago
7

Factor the expression over the complex numbers.

" title=" x^{2} +18" alt=" x^{2} +18" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0

Here we are given the expression:

x^{2}+18

Now let us equate it to zero to find x first,

x^{2}+18=0

Now subtracting 18 from the other side,

x^{2}=-18

taking square root on both sides,

So we will get two values of x as ,

x=3\sqrt{-2}

x=-3\sqrt{-2}

Now we can write square root -1 as i,

So our factors become,

x=3i\sqrt{2}

x=-3i\sqrt{2}

Answer:

The final factored form becomes,

(x+3i\sqrt{2})(x-3i\sqrt{2})



Alona [7]3 years ago
7 0

Answer:

(x+3i\sqrt{2})(x-3i\sqrt{2})

Step-by-step explanation:

1. You must apply the Quadratic formula, which is:

x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}

2. Substitute values:

a=1\\b=0\\c=18

x=\frac{-0+/-\sqrt{0^{2}-4(1)(18)} }{2(1)}\\x=\frac{+/-\sqrt{-72}}{2}\\x=\frac{+/-6i\sqrt{2}}{2}\\x=+/-3i\sqrt{2}

3. Finally, you obtain:

(x+3i\sqrt{2})(x-3i\sqrt{2})

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