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umka21 [38]
3 years ago
9

How many rectangle 5cm multiply 2cm Can fits in a square that has one side 10cm long

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

<u>10</u> rectangles can fit in the square that has one side 10 cm long.

Step-by-step explanation:

Given:

Rectangle 5 cm multiply 2 cm .

Square that has one side 10cm long.

Now, to find the number of rectangle that can fits in the square.

So, for getting the number of rectangle we need to get the area first:

Area of rectangle as given 5 cm multiply 2 cm :

5\ cm\times 2\ cm=10\ cm^2

Then the area of square as given side is 10 cm:

Area of square = (side)²

Area\ of\ square=10^2

Area\ of\ square=100\ cm^2

Now, for getting the number of rectangle we divide the area of square by area of rectangle:

Number of rectangle = Area of square ÷ Area of rectangle

Number\ of\ rectangle=100\ cm^2\div 10\ cm^2

Number\ of\ rectangle=10.

Therefore, 10 rectangles can fit in the square that has one side 10 cm long.

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Select the statement that is FALSE. The range is never greater than the greatest value of a data set. The interquartile range is
Nata [24]

Answer:

The interquartile range is the difference between the highest and lowest values in the middle of a data set.

Step-by-step explanation:

The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.

The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.

The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.

6 0
3 years ago
What is -3x^2-4x-4=0
ss7ja [257]

Answer:

<h2>no real solution</h2>

Step-by-step explanation:

-3x^2-4x-4=0\qquad\text{change the signs}\\\\3x^2+4x+4=0\\\\\text{use the quadratic formula:}\\\\\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then an equation has two solutions:}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{We have}\ a=3,\ b=4,\ c=4.\\\\\text{Substitute:}\\\\b^2-4ac=4^2-4(3)(4)=16-48=-32

8 0
3 years ago
Twenty-one fish are swimming in an aquarium. Eleven are removed, leaving 10 fish. Which number is the additive inverse of the nu
agasfer [191]

The additive inverse: The usage of addition with a negative number.

The original equation is 21 - 11 = 10

To use the additive inverse, change it so that there is an addition sign.

21 + (-11) = 10

B) -11 is your answer

hope this helps

7 0
3 years ago
Read 2 more answers
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi
My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

S_n = \frac{n}{2}(2a_1 +(n-1)d)

Sn = 5510, n=10 n d= 100 we need to find out first term a1

5510 = \frac{10}{2}(2a_1 +(10-1)100)

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

a_n = a_1 + (n-1) d

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0
3 years ago
How do you solve 3px=2q (r-5x) , Solve for x ??
VashaNatasha [74]
Okay for this question the answer is x=0.
5 0
3 years ago
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