C. 14.9 because the second number is 5 so you drop the seven and the 5 and round the 8 up to 9
Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
Step-by-step explanation:
<u>Initial value is the y-intercept:</u>
<u>Rate of change is the difference in the charge amount per year:</u>
- m = (1350 - 1200) / (8 - 5) = 150 / 3 = 50
<u>The equation would be:</u>
Note: 2*2 means 2 times 2
find the factors since
4/8=1/2 because 1/2 times 4/4=4/8
194=2*97
120=2*2*2*3*5
the common number is 2 so divide both by 2
97/60 is the simplest form
in improper fraction form it is
97-60=37
1 37/60
