The center of the circle that circumscribe about DABC is 
.
A circle can be modelled after a expression of the form:
(1)
We can determine all coefficients by knowing three <em>distinct</em> points on plane.
If we know that 
, 
and 
, then the solution of the system of linear equations is:
(2)
(3)
(4)
Now we proceed to <em>complete</em> squares and factor each resulting perfect square trinomial in order to determine the coordinates of the center of the circle:
The center of the circle that circumscribe about DABC is .
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Answer: B) Neither Kelly or Daniel is correct.
A geometric proof is a series of logical reasonings that, starting from a hypothesis, lead to a thesis, using a sequence of statements, axioms, and theorems.
Looking at Kelly's proof, we can say that she is not right. Indeed, she uses the thesis, what she wants to prove, as a justification for her statements.
On the contrary, Daniel uses definitions and properties as a justification for his statements. Although, he does not use the correct justification for statements 1 and 2. Indeed, ∠1 + ∠2 = 180 because they are a linear pair, as well as ∠1 and ∠4.
A linear pair is a pair of adjacent angles formed when two lines intersect, while the supplementary angles definition states that two angles are supplementary when they add to 180 degrees without being necessary next to each other. Since Daniel does not know the effective measure of the angles, he cannot use the definition of supplementary angles.
Hence, neither Kelly or Daniel is correct.
Answer:
0.036
Step-by-step explanation:
0.4 × 0.09 = 0.036
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Answer:
75%
Step-by-step explanation:
Because if u do 90/120 u get 0.75 and divide it by 100 to get %
so the answer is 75%
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Answer:
10%
Step-by-step explanation:
The computation of the percentage of bulbs that switched on incandescent is as follows;
Let us assume the incandescent be I
And, the fluorescent be F
Now the equation is
0.4I + 0.9F = 0.8 (I+F)
0.41I + 0.9F = 0.8I + 0.8F
So here
0.4I = 0.1F
Now the percentage would be for incandescent in the case of switched on is
= 0.4I ÷ 0.8(I+F) × 100
= 0.1F ÷ 1F
= 10%
