Answer:
16.12ft
Step-by-step explanation:
Check attachment
S = 2b + ph
Lets subtract both sides by 2b
s - 2b = ph
Now, divide both sides by h
(s-2b)/h = p
Hope this helps!
<h2>
Answer:</h2>
A. It is a many-to-one function.
<h2>
Step-by-step explanation:</h2>
Hello! It will be a pleasure to help to figure out what's the correct answer to this problem. First of all, we have the following function:

When plotting this function, we get the red graph of the function shown below. So let's solve this as follows:
<h3>A. It is a many-to-one function.</h3>
True
A function is said to be many-to-one there are values of the dependent variable (y-values) that corresponds to more than one value of the independent variable (x-values). To test this, we need to use the Horizontal Line Test. So let's take the horizontal line
, and you can see from the first figure below that
is mapped onto
. so this is a many-to-one function.
<h3>B. It is a one-to-one function.</h3><h3>False</h3>
Since this is a many-to-one function, it can't be a one-to-one function.
<h3>C. It is not a function.</h3>
False
Indeed, this is a function
<h3>D. It fails the vertical line test.</h3>
False
It passes the vertical line test because any vertical line can intersect the graph of the function at most once. An example of this is shown in the second figure below.
Answer:
S_6 = 252
Step-by-step explanation:
We are told that the 10th, 4th and 1st term of an A.P are three consecutive terms of a G.P.
Now,formula for nth term of an AP is;
a_n = a + (n - 1)d
Thus;
a_10 = a + (10 - 1)d
a_10 = a + 9d
Also;
a_4 = a + (4 - 1)d
a_4 = a + 3d
First term is a.
Thus, since they are consecutive terms of a G.P, it means that;
(a + 9d)/(a + 3d) = (a + 3d)/a
Cross multiply to get;
a(a + 9d) = (a + 3d)(a + 3d)
a² + 9ad = a² + 6ad + 9d²
a² will cancel out to give;
9ad - 6ad = 9d²
3ad = 9d²
Divide both sides by 3d to get;
a = 3d
We are told that the first term is 4.
Thus, 4 = 3d
d = 4/3
We saw earlier that ratio of the GP is (a + 3d)/a
Thus; r = (4 + 3(4/3))/4 = 8/4 = 2
Sum of n terms of a G.P is given by;
S_n = a(rⁿ - 1)/(r - 1)
S_6 = 4(2^(6) - 1)/(2 - 1)
S_6 = 252