3 years ago

I need help on number 2 through 9

Mathematics

1 answer:

Phantasy [73]3 years ago

5 0

3: terms/ 12, 8r, -3, s, -5, 15t coefficients/ 8r, 1s, 15t

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Someone help me on question 10 please!

Crazy boy [7]

Answer:

Step-by-step explanation:

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2 years ago

Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she u

Alex787 [66]

Answer with explanation:

Presume that, initial water level to be, 0 mm, at a time t=0.

And water level is rising at the rate of $1.8 \frac{\text{mm}}{\text{year}}$ .

After 6.2 years level of water will be =1.8 × 6.2

=11.16 mm

→Averge, that is increase in water level after 6.2 years is given by

$=\frac{W_{2}-W_{1}}{t_{2}-t_{1}}\\\\=\frac{11.16-0}{6.2-0}\\\\=\frac{11.16}{6.2}\\\\=1.8 \frac{\text{mm}}{\text{year}}$

→→Rate of Depreciating of water level is given by = Negative of Increase of water level= $-1.8 \frac{\text{mm}}{\text{year}}$

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3 years ago

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Factor each expression.<br><br> Problem: 2p^3 + 6p^2 + 3p + 9<br> Answer: (p + 3) (2p2 + 3)

oee [108]

Factor by grouping
$2p^3 + 6p^2 + 3p + 9$
$2 p^3+6 p^2+3 p+9=\left(2 p^3+6 p^2\right)+(3 p+9)=\left(2 p^2\right) (p+3)+3 (p+3)$
$2 p^2 (p+3)+3 (p+3)$
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2 years ago

Three times the quotient of 3 and 5

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Answer:2

Step-by-step explanation:

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2 years ago