There are 2 orange marbles, 3 green marbles, & 5 purple marbles
two consecutives draws <em>without</em> replacement
Orange first, green second
Orange/total = 2/10, or 1/5
green/total - 1 = 3/9, or 1/3
1/5(1/3) = 1/15
There is a 1/15 chance of <em>Orange first, green second</em>
Both marbles are purple
Purple/total = 5/10, or 1/2
Purple/total = 4/9, or <em>44% chance of both being purple</em>
first is purple, the next is anything but purple
purple/total = 1/2, or 50% chance
(everything - purple)/total = 5/10, or 50% chance
1/2(1/2) = 1/4, or 25% chance of <em>first purple, then anything but purple</em>
hope this helps
Answer:
0.01388888888
Step-by-step explanation:
Answer:
Step-by-step explanation:
D: x ≥ -2. This set includes x = -2 and all numbers greater than -2.
Answer:
$2000 is invested at 8%
$2000 is invested at 14%
Step-by-step explanation:
A total of $4000 is invested part at 8% and the remainder at 14%
Annual interest is $440.
Simple interest formula;
I = P × R × T
Where I is the interest, P is the principal, R is the rate and T is the time.
P = $4000
R = 8% and 14%
T = 1 year
I = $440
Let's say $a is invested at 8% and;
$b is invested at 14%
Then,
($a ×
× 1 ) + ($b ×
× 1) = $440
and
$a + $b = $4000
This forms a simultaneous equation;
0.08a + 0.14b = 440 ... (i)
a + b = 4000 ... (ii)
Multiplying (i) by 1 and (ii) by 0.08 we get;
0.08a + 0.14b = 440 ... (i)
0.08a + 0.08b = 320 ... (ii)
Subtracting (i) - (ii) we get;
0 + 0.06b = 120
0.06b = 120
b = 120 ÷ 0.06 = 2000
So amount invested at 14% ($b) = $2000 and,
The amount invested at 8% ($a) = $4000 - $2000 = $2000
Answer:
$ 33.06
Step-by-step explanation:
I Hope this helps :))))