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3 years ago

Which shows 4 written as a percent?

Mathematics

2 answers:

TiliK225 [7]3 years ago

5 0

4 as a percent is 4% or 0.04%

Paha777 [63]3 years ago

3 0

Answer:

400%

Step-by-step explanation:

you have to times 100% to the number to get a percent of that number.

So we have 4, and we times a 100% to it, which makes it 400%.

Hope it helps!

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What is the range and domain of the graph below?

zavuch27 [327]

Answer:

Domain : All real numbers

Range: x<0

Step-by-step explanation:

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3 years ago

For what value of r is the parallelogram a rhombus

Gre4nikov [31]

Answer:

Step-by-step explanation:

7r+18=r²

r²-7r-18=0

factorizing

r²+2r-9r-18=0

r(r+2)-9(r+2=0

(r-9)(r+2)=0

r-9=0

r=9

check

(r²)=(9*9)=81

7r+18=7(9) + 8=81

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3 years ago

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viva [34]

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4 years ago

Read 2 more answers

Describe the rotation of J

Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

J(1, -3)

K(5, 0)

L(8, -4)

M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

3 0

3 years ago

ABC will undergo two transformations to give abc. Which pair of transformations will give a different image of abc if the order

ExtremeBDS [4]

You can consider the triangle (as on in the picture) and apply to it composition of two transformations:
1. reflection about the line y=x to form ΔA'B'C' and translation 1 unit right and 5 units up to form ΔA''B''C'';
2. translation 1 unit right and 5 units up to form ΔA'B'C' and reflection about the line y=x to form ΔA''B''C''.
You can see that results are different.

On added picture blue colour responds to composition of transformations 1 and red colour to composition of transformations 2.

4 0

3 years ago