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2 years ago

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A model is having a scale of 1:100000. how high would a 35600 ft mountain be in the model

1 answer:

Igoryamba2 years ago

4 0

You can cross multiple to find out this one:

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REALLY NEED HELP FOR THIS ALGEBRA 2 QUESTION THANK YOU IN ADVANCE

guajiro [1.7K]

Lets make an equation for the line first. The slope is 3 and the y intercept is -1, so we can make the equation y = 3x - 1. Then, to figure out what sign to use (<= or >= due to solid line in graph), we replace the = sign with one and see if a coordinate in the shaded area will furfill the inequality. If it doesn't, we know it needs the other inequality sign. If it does, we have found the correct inequality. So let's try y <= 3x - 1 with the coordinate (1,1). We try it, solve, and get 1 <= 2. So, the inequality for this graph is y <= 3x - 1.

6 0

2 years ago

Divided 80 by my number, and then added 13. The result was 93. What was my number?

igor_vitrenko [27]

The number is 6400.

We have given that,

divided 80 by my number, and then added 13.

<h3>What is the expression?</h3>

An expression or mathematical expression is a finite combination of symbols that is well-formed according to rules that depend on the context.

Suppose the number is x

$\frac{x}{80}+13=93$

Subtract 13 from both sides

$\frac{x}{80}+13-13=93-13$

$\frac{x}{80}=80$

Multiply both sides by 80

$\\\frac{80x}{80}=80\cdot \:80$

x=6400

Therefore the number is 6400.

To learn more about the number visit:

brainly.com/question/251701

#SPJ1

4 0

1 year ago

WILL GIVE BRAINLEST!!!<br>Find the length of the base.

Nadusha1986 [10]

Answer:

32

Step-by-step explanation:

The length of segment AB is the average of XY and WZ.

(22 + x)/2 = 27

22 + x = 54

x = 32

6 0

1 year ago

In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each

Rudiy27

Answer:

$N(t) = 972(1.015)^{t}$

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

$N(t) = N(0)(1+r)^{t}$

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that $N(0) = 972$

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that $r = 0.015$

Then

$N(t) = N(0)(1+r)^{t}$

$N(t) = 972(1+0.015)^{t}$

$N(t) = 972(1.015)^{t}$

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

$N(t) = 972(1.015)^{t}$

$N(12) = 972(1.015)^{12}$

$N(12) = 1162$

The number of students enrolled in 2014 is 1162.

7 0

2 years ago

Segments CD, AE, and BF are medians of triangle ABC.

EleoNora [17]

Option C: x = 5.5 is the value of x

Explanation:

Given that CD, AE, an BF are the medians of the triangle ABC

Also, given that $AM = 4x - 5$ and $ME=x+3$

We need to determine the value of x.

Since, we know that the centroid divides the median in the ratio 2 : 1

Hence, we have,

$AM=2\times ME$

Substituting the values, we get,

$4x-5=2(x+3)$

Simplifying, we get,

$4x-5=2x+6$

Subtracting both sides of the equation by 2x, we have,

$2x-5=6$

Adding both sides of the equation by 5, we have,

$2x=11$

Dividing both sides of the equation by 2, we get,

$x=5.5$

Therefore, the value of x is 5.5

Hence, Option C is the correct answer.

7 0

3 years ago