Please help again!! super desperate ahhh !!

A farmer owns about 960 acres of land. If his farm is square, what would be the length of each side in miles, to the nearest ten

OLEGan [10]

It is given in the question that

A farmer owns about 960 acres of land. If his farm is square.

First we convert acres to miles square, and the conversion expression is

$1 acre=0.0015625 mi^2$

Therefore,

$960acres=960*0.0015625=1.5 mi^2$

Let the side length of the square be x miles .

And the formula of area of square is

$Area=side^2
\\
1.5=side^2
\\
side= \sqrt{1.5}=1.2 miles$

5 0

2 years ago

Ed Parker joined a health club. There was a $49 registration fee, and a $17.50 monthly fee. If Ed visits the club 2 times a week

Allushta [10]

He should would have to pay 298.

6 0

3 years ago

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HELP PLEASE WILL MARK BRAINLIEST!!

lilavasa [31]

Answer:

the picture is blurry sorry can't help cause I can't see the question

4 0

3 years ago

Which of the following equations will produce the graph shown below?

melisa1 [442]

The graph is a circle, centered at the origin, with radius=4.

We know that we can write the equation of a circle with radius r and center (a,b) as :

$(x-a)^2+(y-b)^2=r^2$ .

Thus, substituting (a, b) with (0, 0) and r with 4, we have:

$x^2+y^2=16$ .

The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:

$x^2+y^2=16\\\\x^2+y^2-16=0\\\\2(x^2+y^2-16)=0$ ,

we would still have the same roots.

Thus, the equation of the circle can be written as :

$2x^2+2y^2=32$ .

Answer: B

5 0

3 years ago

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Three polynomials are factored below, but some coefficients and constants are missing. All of the missing values of a, b, c, and

mariarad [96]

9514 1404 393

Answer:

(a, b, c, d) = (1, -4, 1, -2)
(a, b, c, d) = (1, -4, 1, 2)
(a, b, c, d) = (1, -4, 2, 6)

Step-by-step explanation:

Once you remove the common factor from the terms, you are looking for factors of the remaining constant term that have a sum equal to the coefficient of the linear term. These factors are the constants in the binomial factors.

__

1. 8 = (-4)(-2) ⇒ x^2 -6x +8 = (x -4)(x -2)

(a, b, c, d) = (1, -4, 1, -2)

__

2. -8 = (-4)(+2) ⇒ 3x^3 -6x^2 -24x = 3x(x -4)(x +2)

(a, b, c, d) = (1, -4, 1, 2)

__

3. -12 = (-4)(3) ⇒ 2x^2 -2x -24 = 2(x -4)(x +3) = (x -4)(2x +6)

(a, b, c, d) = (1, -4, 2, 6) or (2, -8, 1, 3)

3 0

2 years ago