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Nostrana [21]
3 years ago
8

Why do you subtract exponents when dividing powers with the same base?

Mathematics
1 answer:
enyata [817]3 years ago
5 0

Because the factors in the numerator cancel with the factors in the denominator. Consider this example:

\dfrac{6^7}{6^4} = \dfrac{6\times6\times6\times6\times6\times6\times6}{6\times6\times6\times6} = 6\times6\times6 = 6^3 = 6^{7-4}

All of the 6's in the denominator canceled with the 6's in the numerator, and only 3 6's "survived". The opposite can also happen, if there are more terms in the denominator:

\dfrac{2^2}{2^4} = \dfrac{2\times 2}{2\times 2\times 2 \times 2} = \dfrac{1}{2^2} = 2^{-2} = 2^{2-4}

So, everything is coherent

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Answer:

Expression I and IV

Step-by-step explanation:

Expression I simplified :

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2 years ago
Consider the function g(x) = 10/x
ss7ja [257]
<span><span>The correct answers are:
</span><span>(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

</span><span>Explanation:
</span><span>(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = </span></span>\frac{10}{x}<span>

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = </span>\frac{10}{x}<span>

We can write it as:

g(x) = </span>\frac{10 * x^0}{x^1}<span>

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
</span>
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3 years ago
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Could someone please help me with this?
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21.5 mm^2

Step-by-step explanation:

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A = s^2 = 10^2 =100

Then find the area of the circle

d = 10 so r = d/2 = 10/2 =5

A = pi r^2

A = 3.14 (5)^2 =78.5

The difference is the shaded region

100-78.5 =21.5

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son4ous [18]
3:9 and if you reduce it again, 1:3
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2 years ago
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Answer:

0.13 cents

Step-by-step explanation:

1.99 / 15 = 0.1326, rounded is 0.13

3 0
3 years ago
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