Answer:
y = 30.96
Step-by-step explanation:
take 23 degree as reference angle
using tan rule
tan 23 = opposite / adjacent
0.42 = 13/y
y = 13/0.42
y = 30.96
Answer:
Last Year Length = 4 meters
This Year Length = 12 meters
This Year Width = 10 meters
Step-by-step explanation:
We know, area of the rectangle is given by the formula:
Area = Length * Width
Given width = 5
Area = 20
We solve for Length:
Area = Length * Width
20 = Length * 5
Length = 20/5 = 4
Last Year Length = 4 meters
Now, this year, the length would be 3 times as long, so new length would be:
This Year Length = 4 * 3 = 12 meters
This year, the width would be two times previous year, so width would be:
This Year Width = 5 * 2 = 10 meters
The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) <span>Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "
</span>
It is assumed that the points are
A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4).
<span>A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).</span>
Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"
Recall that to calculate the distance between two points (a,b) and (c,d) we use the formula
![\sqrt[]{(c-a)^2+(d-b)^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%28c-a%29%5E2%2B%28d-b%29%5E2%7D)
In our case we have a=-2, b=5, c=4 and d=5. So we get
![\sqrt[]{(4-(-2))^2+(5-5)^2}=\sqrt[]{6^2}=6](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%284-%28-2%29%29%5E2%2B%285-5%29%5E2%7D%3D%5Csqrt%5B%5D%7B6%5E2%7D%3D6)
So the distance between both points is 6
Answer:
Function 1 has a greater slope and greater<em> y</em>-intercept than Function 2.
Step-by-step explanation:
Function 1
Slope: 1/3
<em>y</em>-intercept: 2
Function 2
Slope: -2/4
<em>y</em>-intercept: -2
