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alukav5142 [94]

2 years ago

13

Find the missing lengths.

1 answer:

Rama09 [41]2 years ago

4 0

Answer:

x = 5√2

Step-by-step explanation:

The triangle on the right is a special right triangle, so we know that the adjacent side to 60° is 5. Since the left triangle is a 45-45-90, the hypotenuse is the leg times √2, so the value of x is 5√2

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Circle U is shown. Chords R T and Q S intersect at a point forming 4 angles. The top left angle is angle 1, and the top right an

Dima020 [189]

Based on the calculations, the measures of angles 1 and 2 are 50° and 135° respectively.

<h3>What is the theorem of intersecting chord?</h3>

The theorem of intersecting chord states that when two (2) chords intersect inside a circle, the measure of the angle formed by these chords is equal to one-half (½) of the sum of the two (2) arcs it intercepts.

By applying the theorem of intersecting chord to circle U shown in the image attached below, we can infer and logically deduce that angle 1 will be given by this formula:

m∠1 = ½(53 + 47)

m∠1 = ½(100)

m∠1 = 50°.

Since angles 1 and 2 are linear pair, they are supplementary angles. Thus, we have:

m∠1 + m∠2 = 180°

m∠2 = 180 - m∠1

m∠2 = 180 - 50

m∠2 = 130°.

Read more on intersecting chords here: brainly.com/question/27251228

#SPJ1

6 0

1 year ago

Read 2 more answers

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

How many solutions does the system of equations have y=5x+7 and 3y-15x=18

spayn [35]

Hello there.

<span>How many solutions does the system of equations have y=5x+7 and 3y-15x=18

</span><span>B two
</span>

6 0

3 years ago

Read 2 more answers

100 POINTS IF U GET THIS RIGHT !

cluponka [151]

Pretty sure the correct answer is 9/25

5 0

2 years ago

Read 2 more answers

What’s the area all sides meet at right angles

Marina86 [1]

Answer: 54

Step-by-step explanation: I separated it into 3 areas in my head and then added up 21+21+12 to get 54

7 times 3 is 21

7 times 3 is 21

and

3 times 4 is 12

sorry if i am wrong i just did this in my head

8 0

2 years ago