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DedPeter [7]
4 years ago
5

What is the name of an equivalent name for 96

Mathematics
2 answers:
Aleksandr-060686 [28]4 years ago
8 0
For this case we have the following number:
 96
 We can rewrite this number in an equivalent way.
 For example, we can use words to rewrite the number.
 We have then:
 96 = ninety six
 Answer:
 
the name of an equivalent name for 96 is:
 
Ninety-six
katovenus [111]4 years ago
8 0
An equivalent name for 96 is ninety-six. Word form is equivalent to number form. I hope I helped!
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Aleksandr [31]

Answer:

Yes because you will still be able to get a Number that will verify.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1. Find the exact value of sin and cos of 195 degrees.
KengaRu [80]

Answer:

Sin195* = -\frac{\sqrt{6}-\sqrt{2}  }{4 }

Cos195* = - \frac{\sqrt{6} +\sqrt{2} }{4}

Step-by-step explanation:

5 0
3 years ago
Ask Your Teacher The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particula
Georgia [21]

Answer:

The level is L = 0.084

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 0.08, \sigma = 0.01, n = 36, s = \frac{0.01}{\sqrt{36}} = 0.0017

What is the level L such that the probability that the average NOX level x for the fleet is greater than L is only 0.01?

This is X when Z has a pvalue of 1-0.01 = 0.99. So it is X when Z = 2.325.

Z = \frac{X - \mu}{\sigma}

By the Central limit theorem

Z = \frac{X - \mu}{s}

2.325 = \frac{X - 0.08}{0.0017}

X - 0.08 = 2.325*0.0017

X = 0.084

The level is L = 0.084

4 0
4 years ago
What is the length of the unknown leg to the nearest tenth?
Karolina [17]

Answer:

A

Step-by-step explanation:

a^2 + b^2 = c^2

a^2 + 100 = 256

a^2 = 156

a = 12.48

a = 12.5

6 0
4 years ago
For the next six month period Sammy wants to calculate the monthly deviation from the average.
jek_recluse [69]

Answer:

Deviation:

July ----- 289.17

August ----- 339.17

September ----- 14800.17

October ----- -65.83

November ----- 10690.17

December ----- -480.83


3 0
3 years ago
Read 2 more answers
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