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alexandr1967 [171]
3 years ago
12

Given A={x ∈ Z : x is even}, B={x ∈ Z : x is prime number}, C={x ∈ Z : x is odd}, and D={5, 7, 8, 12, 13, 15}.

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

a) {15}

b) { }

c) D or {5, 7, 8, 12, 13, 15}

d) no

e) yes

Step-by-step explanation:

a) AUB: even or prime

D - (AUB) = {15}

b) AUC: even or odd; basically all integers

D - (AUC) = { }

c) A∩B : even and prime, that's only 2

D - (A∩B) = {5, 7, 8, 12, 13, 15} = D

d) A and B, both contain 2

Not disjoint

e) A and C are disjoint because no number can be both, even and odd

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Answer:

(a) ∠DAB  = 59°

(b) ∠A  = 135°

(c)  ∠A   = 99°

Step-by-step explanation:

<u>Theorem</u>: If a quadrilateral is inscribed inside a circle, then the opposite angles of the quadrilateral are SUPPLEMENTARY.

So, here in the given figures:

(1) ∠DCB +   ∠DAB  = 180°  (as opposite angles are supplementary)

⇒∠DAB   =  180°  -   121°   =  59°

or, ∠DAB  = 59°

(2) ∠DCB +   ∠DAB  = 180°  (as opposite angles are supplementary)

⇒(3x+6) + (x+2) = 180° or, 4x = 180 - 8 = 172

⇒ x = 172/4 = 43, or x  = 43

So, ∠A  = (3x+6)  =  3(43) + 6 = 135°

(3) (28) +  (x) = 180°

or, x =  180 - 28 = 152

So, ∠A  = (x- 36)  =  135 - 36  = 99°

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