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alexandr1967 [171]
3 years ago
12

Given A={x ∈ Z : x is even}, B={x ∈ Z : x is prime number}, C={x ∈ Z : x is odd}, and D={5, 7, 8, 12, 13, 15}.

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

a) {15}

b) { }

c) D or {5, 7, 8, 12, 13, 15}

d) no

e) yes

Step-by-step explanation:

a) AUB: even or prime

D - (AUB) = {15}

b) AUC: even or odd; basically all integers

D - (AUC) = { }

c) A∩B : even and prime, that's only 2

D - (A∩B) = {5, 7, 8, 12, 13, 15} = D

d) A and B, both contain 2

Not disjoint

e) A and C are disjoint because no number can be both, even and odd

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Student to faculty is 17:3 The total is 740 how many students and faculty are at the college
inn [45]
Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y=  740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
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faltersainse [42]

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Step-by-step explanation:

Let,

Price of one vegetarian special lunch = x

Price of one chicken special lunch = y

According to given statement;

21x+40y=467      Eqn 1

28x+36y=484     Eqn 2

Multiplying Eqn 1 by 28

28(21x+40y=467)\\588x+1120y=13076\ \ \ Eqn\ 3

Multiplying Eqn 2 by 21

21(28x+36y=484)\\588x+756y=10164\ \ \ Eqn\ 4

Subtracting Eqn 4 from Eqn 3

(588x+1120y)-(588x+756y)=13076-10164\\588x+1120y-588x-756y=2912\\364y=2912

Dividing both sides by 364

\frac{364y}{364}=\frac{2912}{364}\\y=8

Putting y=8 in Eqn 1

21x+40(8)=467\\21x+320=467\\21x=467-320\\21x=147

Dividing both sides by 21

\frac{21x}{21}=\frac{147}{21}\\x=7

The price of one vegetarian special lunch is $7 and price of one chicken special lunch is $8.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/10081622
  • brainly.com/question/10341324

#LearnwithBrainly

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Step-by-step explanation:

that is what I found on the internet

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