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3 years ago

Which number line would not describe a situation where the midpoint between points A and B is 2 1/2?

Mathematics

2 answers:

andre [41]3 years ago

8 0

Answer: (-4, 8)

Options (A, B):
1. (2, 3)
2. (-4, 9)
3. (-4, 8)
4. (-0.75, 5.75)

inessss [21]3 years ago

4 0

Answer:

Option C

Step-by-step explanation:

We know that in a number line numbers all (rational preferably) would be marked on a line in a chronological order.

Mid point of A and B would be the average value of A and B.

Here given that mid point is 2 1/2

This implies average of A and B is 2 1/2

Or total of A and B should be 5

Out of 4 options let us check which gives total 5.

A) (2,3) .. Total is 5

B) (-4,9)..Total is again 5

C) (-4,8)..Total is not 5 but 4

D) (-0.75, 5,75) .. Total is 5

So out of these 4 options only C would not describe a situation where the midpoint between points A and B is 2 1/2

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3 years ago

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3 years ago

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2 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago