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Sphinxa [80]
3 years ago
9

According to an​ article, 36​% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select

ed​ adults, find the probability that the​ number, X, who have experienced a breakup at least once during the last 10 years is
Mathematics
1 answer:
enot [183]3 years ago
7 0

Title:

<h2>See the explanation.</h2>

Step-by-step explanation:

The probability that an adult will experience breakup at least once during the last ten years is \frac{36}{100} = 0.36.

Hence, the probability that the adult will not experience breakup is (1 - 0.36) = 0.64.

As per the given question, X is the number of adults who face breakup. From the 9 people X persons can be chosen in ^9C_X ways.

The probability that X persons will experience breakup is ^9C_X \times (0.36)^X \times (0.64)^{9 - X}.

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