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Minchanka [31]
3 years ago
5

An 8 foot long piece of 2 by 4 wood is used to prop up a fence if the 2 by 4 makes 30 degree angle with the ground how high abov

e the ground is the point where the 2 by 4 contacts the fence

Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

4

Step-by-step explanation:

H (height the 2x4 contact the fence)

sin 30° = H / 8

1 /2 = H / 8

H = 1/2 * 8 = 4

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Find the value of x in the isosceles triangle shown below.
Reptile [31]

Answer:

x=10

Step-by-step explanation:

We can use the Pythagorean theorem to find x

The height meets the base at a right angle

The base is bisected ( cut in half) so the base is 6 the height is 8

a^2 + b^2 = c^2

6^2 + 8^2 = x^2

36+64 = x^2

100 = x^2

Taking the square root of each side

sqrt(100) = sqrt(x^2)

10 = x

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Which following fractions is equivalent to 0.45
vladimir1956 [14]

0,45=\frac{45}{100} =\frac{9}{20}

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The flagpole in Mario's yard is 3,000 centimeters tall. How many meters tall is the flagpole?
Rzqust [24]
3000/100 = 30.  When you go from Centimeters to Meters you divide by 100.

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3 years ago
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If a building was placed at coordinates (-5,5), what would be the new coordinates if rotated 270° counterclockwise around the or
Brums [2.3K]

The rule for a 270° counterclockwise rotation is (x, y) ---> (y, -x).

So if you rotated (-5,5) 270° counterclockwise around the origin the new coordinates would be (-5,-5).

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HELP 40 POINTS
Tom [10]
Answer: the function g(x) has the smallest minimum y-value.


Explanation:


1) The function f(x) = 3x² + 12x + 16 is a parabola.


The vertex of the parabola is the minimum or maximum on the parabola.


If the parabola open down then the vertex is a maximum, and if the parabola open upward the vertex is a minimum.


The sign of the coefficient of the quadratic term tells whether the parabola opens upward or downward.


When such coefficient is positive, the parabola opens upward (so it has a minimum); when the coefficient is negative the parabola opens downward (so it has a maximum).


Here the coefficient is positive (3), which tells that the vertex of the parabola is a miimum.


Then, finding the minimum value of the function is done by finding the vertex.

I will change the form of the function to the vertex form by completing squares:

Given: 3x² + 12x + 16

Group: (3x² + 12x) + 16
Common factor: 3 [x² + 4x ] + 16
Complete squares: 3[ ( x² + 4x + 4) - 4] + 16
Factor the trinomial: 3 [(x + 2)² - 4] + 16
Distributive property: 3 (x + 2)² - 12 + 16
Combine like terms: 3 (x + 2)² + 4

That is the vertex form: A(x - h)² + k, whch means that the vertex is (h,k) = (-2, 4).


Then the minimum value is 4 (when x = - 2).


2) The othe function is <span>g(x)= 2 *sin(x-pi)
</span>

The sine function goes from -1 to + 1, so the minimum value of sin(x - pi) is - 1.


When you multiply by 2, you just increased the amplitude of the function and obtain the new minimum value is 2 (-1) = - 2


Comparing the two minima, you have 4 vs - 2, and so the function g(x) has the smallest minimum y-value.

7 0
3 years ago
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