Answer:
To write a linear equation in standard form, move each variable term to the left side of the equation and simplify.
A
x
+
B
y
=
C
Since
x
is on the right side of the equation, switch the sides so it is on the left side of the equation.
3
x
−
2
=
y
Move
y
to the left side of the equation because it contains a variable.
3
x
−
2
−
y
=
0
Move
2
to the right side of the equation because it does not contain a variable.
3
x
−
y
=
2
Step-by-step explanation:
4x-8=9y-5 in standard form is 4x-9y=3
Answer: ![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
You know that the expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D)
By definition we know that:
![\sqrt[n]{a}=a^{\frac{1}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D)
You also need to remember the Quotient of powers property:
Therefore, you can rewrite the expression:
Finally, you have to simplify the expression. Therefore, you get:
![=2^{(\frac{1}{2}-\frac{1}{3})}\\=2^{\frac{1}{6}}\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%3D2%5E%7B%28%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%29%7D%5C%5C%3D2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)
y = | x -5| + |x+5|
as range of x is
-5 < x < 5
we can see if we put x = 0 we get
y = 10
we put any value of x in given range first term is always negative without absolute. and 2nd term is always positive
so
y = | x -5| + |x+5|
= -( x-5) + x + 5
= - x + 5 + x + 5
= 10
so
y = 10 where -5 < x < 5
