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andreev551 [17]
3 years ago
11

a race car slows down to make a turn. If it has an initial velocity of 180 km/h [S] and accelerates at a rate of 8.2 m/s squared

[N] for 3.2 s at what velocity (in kilometers per hour) does it accelerate
Mathematics
1 answer:
kherson [118]3 years ago
6 0
Race car 2
Muiltple Answers
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Find the area of the figure. Use 3.14 as π.
Karolina [17]

Answer: D. 94.25 in²

Step-by-step explanation:

To find the total area, we will break the shape up into two different parts.

[] The rounded part is 39.25 in². Let us assume the rounded part is exactly half of a circle.

      Area of a circle:

A = πr²

      Use 3.14 for pi:

A = (3.14)r²

      Find the radius:

d / 2 = r, 10 / 2 = 5 in

      Subsittue:

A = (3.14)(5)²

A = 78.5 in²

      Divide by 2 since it is only half:

78.5 in² / 2 = 39.25 in²

[] The triangle is 55 in².

      Area of a triangle:

A = b*h/2

A = 11 * 10 / 2

A = 110 / 2

A = 55 in²

[] Total area. We will add the two parts together.

55 in² + 39.25 in² = 94.25 in²

7 0
2 years ago
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Solver r=1/2m2p for p
Kisachek [45]

Answer:

p= 2r/m^2

Step-by-step explanation:

7 0
3 years ago
Select the best answer for the question
kozerog [31]
X=9 this is the answer for question 19

6 0
3 years ago
What is 8c + c = , is it 8cc, 9c, 8c2, 8c
Mnenie [13.5K]

Answer:

9c

Step-by-step explanation:

if you take 8c and add another c, it equals 9c

8 0
3 years ago
Confusion...help please
kifflom [539]

Given:

In triangle KLM, KL = 123 cm and measure of angle K is 35 degrees.

To find:

The length of the side KM to the nearest tenth of a centimeter.

Solution:

In a right angle triangle,

\cos \theta =\dfrac{Base}{Hypotenuse}

In the given right triangle KLM,

\cos K=\dfrac{KM}{KL}

\cos (35^\circ)=\dfrac{KM}{123}

0.819152=\dfrac{KM}{123}

Multiply both sides by 123.

0.819152\times 123=KM

100.755696=KM

KM\approx 100.8

The measure of side KM is 100.8 cm.

Therefore, the correct option is (2).

8 0
3 years ago
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