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romanna [79]
3 years ago
9

If the circumference of a circle is 12.56 ft what is the diameter?​

Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0
The diameter would be 4ft

Hope this helped :)
Karo-lina-s [1.5K]3 years ago
4 0

Answer:

4 ft is the diameter

Step-by-step explanation:

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A sno-cone machine priced at $139 is on sale for 20% off. The sales tax rate is 6.75%. What is the price of the sno-cone machine
trapecia [35]

Answer:

$127.03

Step-by-step explanation:

A snow cone machine price at $139 is on after for 20 off.

The price after discount=139-20=$199

The sale tax rate 6.75%

Price with sales tax=199+(6.75%×199)

=199+(0.0675×199)

= 199+8.03

=<em>$</em><em>1</em><em>2</em><em>7</em><em>.</em><em>0</em><em>3</em>

4 0
3 years ago
Can someone help me please
snow_tiger [21]

Answer:

Here you go

Step-by-step explanation:

BTW what is meant by point in the last blank?

6 0
3 years ago
Read 2 more answers
The equation for the circle below is the x2 + y2=81. what is the length of the circles radius
larisa [96]

Answer:

9

Step-by-step explanation:

Compare your x2 + y2=81 to the following:

                       x^2 + y^2 = 81

The " ^ " symbol indicates exponentiation.

Now compare  x^2 + y^2 = 81 to

                         x^2 + y^2 = r^2.  

This is the standard equation of a circle of radius r centered at the origin, (0,0).  You can see for yourself that 81 must equal r^2.


Taking the square root of 81, we get plus or minus 9.

But the radius must be positive, so we reject the -9 and take +9.

The radius is 9.

8 0
3 years ago
Read 2 more answers
f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.
yuradex [85]

Given:

The function is

f(x)=\dfrac{4x}{x^2-16}

To find:

The asymptotes and zero of the function.

Solution:

We have,

f(x)=\dfrac{4x}{x^2-16}

For zeroes, f(x)=0.

\dfrac{4x}{x^2-16}=0

4x=0

x=0

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

x^2-16=0

x^2=16

Taking square root on both sides, we get

x=\pm \sqrt{16}

x=\pm 4

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

8 0
3 years ago
Please help with this question. I need an answer ASAP!! I need help! I don't understand this!
Romashka-Z-Leto [24]

Answer: 42°

<u>Step-by-step explanation:</u>

HJ is an angle bisector of ∠IHK so

∠IHJ ≅ ∠KHJ ⇒ m∠IHJ = m∠KHJ

                           3a + 6 = 5a - 18

                                   6  = 2a - 18

                                  24 = 2a

                                   12 = a

∠IHJ = 3a + 6

        = 3(12) + 6

        = 36 + 6

         = 42

8 0
3 years ago
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