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Butoxors [25]
3 years ago
10

In an examination 25percent of them failed to obtain the pass mark. The number of candidates who passed was 150 . How many candi

dates failed​
Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
25% candidates failed
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5. Solve each equation by systematic trial.
Basile [38]

Answer:

a) x = 260

b) g = 218

c) z = 30

d) h = 5

Step-by-step explanation:

a) x-68=192

Predict a number; let's say x = 225

225-68=192\\157=192

Too low; try with a higher number; let's say x = 270

270-68=192\\202=192

Too high, we're closer.

x = 260

260-68=192\\192=192

--------------------------------------------------------------------------------------

b) g+33=251

let's say g = 230

230+33=251\\263=251

Too high. Try g = 221

221+33=251\\254=251

We're almost there. Let's try with g = 218

218+33=251\\251=251

----------------------------------------------------------------------------------------

c) 3z-16=74

Let's try with z = 15

3(15)-16=74\\45-16=74\\29=74

Too low; try a higher number. z = 30

3(30)-16=74\\90-16=74\\74=74

--------------------------------------------------------------------------------------------

d) 15h+9=84

Let's try with h = 6

15(6)+9=84\\90+9=84\\99=84

Too high; let's try with h = 5

15(5)+9=84\\75+9=84\\84=84

3 0
3 years ago
In the reaction of hydrogen with iodine
Bond [772]

Answer:

HI hydrogen iodide

Step-by-step explanation:

H2(gas)+I2(gas)---------->2HI(gas)

6 0
3 years ago
Read 2 more answers
I need you to give me all of the answers on the page (i answered 2 to show how you will be doing it)
Phantasy [73]

Answer:

3. 72= (x)+(x+1)+(x+2) where x= the smallest number

72=3x+3

-3        -3

69=3x

/3   /3

x=23

x+1=24

x+2=25

smallest is 23

4. 48= (x)+(x+2)+(x+4)

48= 3x+6

-6        -6

42=3x

/3    /3

x=14

x+2=16

x+4=18

smallest is 14

5. all erasers were the same cost

25= 4x+5 (x= cost of erasers)

-5         -5

20=4x

/4   /4

x=5

each cost  $5

6. b= boxes

22= b/2 +7

-7            -7

15=b/2

multiply both sides by 2 to cancel the denominator

30=b

30 boxes originally

7. 40= total

8= left

2= balls given to each

x=number of friends

40= 2x+8

-8         -8

32=2x

/2   /2

x=16

she has 16 friends

8.  12= left

a= total allowance

12= (a/2) +4

-4            -4

8= a/2

multiply both sides by 2 to cancel the denominator

a= $16

she had an allowance of $16

9.  4 (2) = amount that her four children recieved

10=amount she took for herself

x= original

x= 4(2) + 10

x= 8 +10

x=18

she started with 18 candies

10. a= age

244= 400 - 2a

-400 -400

-156= -2a

/-2     /-2

a= 78

they are 78 years old

11. c= comic books

36=  c/2 + 16

-16           -16

20=c/2

multiply both sides by 2 to cancel the denominator

c=40

she started with 40 comic books

12.  b= students in buses

472= 9b + 4

-4             -4

468=9b

/9     /9

b= 52

52 students went in each bus

13. h= hats

17= h/2 +5

-5          -5

12=h/2

multiply both sides by 2 to cancel the denominator

h=24

she had 24 hats on monday

14. p= pies the club made

60= (p+4)/5

multiply both sides by 5 to cancel the denominator

300=p+4

-4         -4

p= 296

the club made 296 pies

Step-by-step explanation:

5 0
3 years ago
HELP PLEASE!!!!!!!!!!!! ITS DUE SOON
Bad White [126]

Use a factor tree to express 60 as a product of prime factors. So the prime factorization of 60 is 2 × 2 × 3 × 5, which can be written as 2 2 × 3 × 5. The actual prime factors of 60 are 2, 3, and 5.

7 0
3 years ago
Determine the they value of 5(×+2)-4 when x=5
coldgirl [10]
When  x=5 ,

5(x+2) - 4  =  5(5+2) - 4  =  5(7) - 4  =  35 - 4  =  <em>31</em>
6 0
3 years ago
Read 2 more answers
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