Answer:i cant see it good
Step-by-step explanation:
Answer:
The arrow is at a height of 48 ft after approximately <u>0.55</u> s and after <u>5.45</u> s
Step-by-step explanation:
The following information is missing:
<em>The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? </em>
If the arrow is at a height of 48 ft and its initial velocity is 96 ft/s, then:
48 = 96*t - 16*t²
16*t² - 96*t + 48 = 0
16*(t² - 6*t + 3) = 0
t² - 6*t + 3 = 0
t² - 6*t + 3 + 6 = 0 + 6
t² - 6*t + 9 = 6
(t - 3)² = 6
t - 3 = √6
t - 3 = 2.45; t = 2.45 + 3; t = 5.45
or
t - 3 = -2.45; t = -2.45 + 3; t = 0.55
4c + 6a < = 120 ...4(20) + 6(6) = 116 <== correct
4c + 4a < = 100....4(20) + 4(6) = 104 <== incorrect
first answer choice
Step-by-step explanation:
Answer
Radius = 6 cm
Surface area = 2πr(r+h)
=2×
7
22
×6×(6+8)
=528 cm
2
