Answer:
P = 321.3m
Step-by-step explanation:
To help simplify the process of solving this problem, first break it up into different shapes. Here, you have two shapes: a rectangle and a circle (1 semi-circle + 1 semi-circle = 1 circle).
Next, use the equation for circumference of a circle to find the first part of the perimeter (C = πd). In this case, the diameter would be 45m.
- C = πd
- C = 3.14 × 45
- C = 141.3 m
This is the first part of the circumference. Now, you must consider the rectangle. (Because the two shorter sides of the rectangle are not part of the perimeter, do not include these in your final answer.) The length of the rectangle is 90 meters, and since both sides that measure to 90m are part of what makes up the perimeter, lastly add these to the circumference you calculated earlier.
- (90 + 90) or (90 × 2) = 180
- P = 141.3 + 180
- P = 321.3m
Hope this helps! : )
Answer:
f(-3) = -20
Step-by-step explanation:
We observe that the given x-values are 3 units apart, and that the x-value we're concerned with is also 3 units from the first of those given. So, a simple way to work this is to consider the sequence for x = 6, 3, 0, -3. The corresponding sequence of f(x) values is ...
34, 10, -8, ?
The first differences of these numbers are ...
10 -34 = -24
-8 -10 = -18
And the second difference is ...
-18 -(-24) = 6
For a quadratic function, second differences are constant. This means the next first-difference will be ...
? -(-8) = -18 +6
? = -12 -8 = -20
The value of the function at x=-3 is -20.
_____
The attachment shows using a graphing calculator to do a quadratic regression on the given points. The graph can then be used to find the point of interest. There are algebraic ways to do this, too, but they are somewhat more complicated than the 5 addition/subtraction operations we needed to find the solution. (Had the required x-value been different, we might have chosen a different approach.)
Solution:
The given Polynomial is :

By Rational Root theorem the of Zeroes of the Polynopmial are:

But , 
So, no root of this polynomial is real.
Therefore, All the four roots of Polynomial are imaginary.
So, we can't say whether the number k=2, is an upper or lower bound of the polynomial
.
Answer:
all real numbers greater than or equal to 2
which is [2, infinite)